Answer:
Width=28 1/3 Length=51 2/3
Step-by-step explanation:
1. Create an equation
x+(2x-5)=80
2. Solve
x+(2x-5)=80
3x-5=80
3x-5+5=80+5
3x/3=85/3
x=28 1/3
So, if x=28 1/3
85/3x2=170/3
56 2/3-5
So, Length=51 2/3
So,
Optimally, we want a number between 1 and 10 multiplied by a power of ten.
If we move the decimal place 6 places to the right, we get 6.
So we want

.
The correct option is C.

solve for "k", to find k or the "constant of variation"
then plug k's value back to

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is
H=how far up from the ground does the ladder touch the building
h/30=sin 25°
h=30 sin 25°
h=12.7 decimeters(1 decimal place)
Answer: The height that the ladder touch the building far up from the ground is 12.7 decimeters.
<span>2a(7a²-3a+9)
=14a^3 - 6a^2 +18a
answer is </span><span>D. 14a³-6a²+18a</span>