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KiRa [710]
3 years ago
10

What is the distributive property for 6x+18=5(3x+9)

Mathematics
2 answers:
vredina [299]3 years ago
6 0

Answer:

-3 =x

Step-by-step explanation:

6x+18 = 5(3x+9)

Distribute the 5

6x+18 = 15x+45

Subtract 6x from each side

6x+18-6x =15x-6x +45

18 = 9x+45

Subtract 45 from each side

18-45 =9x+45-45

-27 = 9x

Divide by 9

-27/9 = 9x/9

-3 =x

babunello [35]3 years ago
3 0

Answer:

6(x+3)=15(x+3)

Step-by-step explanation:Find the common factor of 6 and 18, which is 6. So you would put 6 outside of the parenthesis and the other factors multiplied by it inside the parenthesis(x and 3). If this is confusing then then in other words the common multiple of 6x and 18 is 6 so 6 divided by 6x is x so x goes in the parenthesis and 18 divided by 6 is 3 so 3 also goes in the parenthesis.that is what 6(x+3) stands for. I also simplified 15(x+3)by solving it to see it meant 15x+45 and the GFC(greatest common factor) is 15 and 15x divided by 15 is x and 45 divided by 15 is 3, so the GCF(15) goes outside the parenthesis and you put x and 3 inside the parenthesis.Which explains to you the 15(x+3). Hope this helps!


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5 0
3 years ago
The difference between of two numbers is 9. If the large number is one more than twice the smaller number, find the larger numbe
sleet_krkn [62]

The larger number is 17

<em><u>Solution:</u></em>

Let "x" be the larger number

Let "y" be the smaller number

<em><u>The difference between of two numbers is 9</u></em>

Therefore,

larger number - smaller number = 9

x - y = 9 -------- eqn 1

<em><u>The large number is one more than twice the smaller number</u></em>

Larger number = 1 + 2(smaller number)

x = 1 + 2y ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 2 in eqn 1</u></em>

1 + 2y - y = 9

1 + y = 9

y = 9 - 1

y = 8

<em><u>Substitute y = 8 in eqn 1</u></em>

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7 0
3 years ago
Simplify this please​
Ugo [173]

Answer:

\frac{12q^{\frac{7}{3}}}{p^{3}}

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. (a^{x})^{n} = a^{xn}

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). a^{-x} = \frac{1}{a^{x}}, and to help with this question: \frac{a^{-x}b}{1} = \frac{b}{a^{x}}.

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. (a^{x})(a^{y}) = a^{x+y}

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. \frac{a^{x}}{a^{y}} = a^{x-y}

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}

\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}        Distribute exponent

=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}        Simplify each exponent by multiplying

=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}        Negative exponent rule

=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}        Combine the like terms in the numerator with the base "q"

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}        Rearranged for you to see the like terms

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}        Multiplying exponents with same base

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}        2 + 1/3 = 7/3

=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}        Fractional exponents as radical form

=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.

=\frac{(4)(3)(p)(q^{\frac{7}{3}})}{p^{4}}        Multiply 4 and 3

=\frac{12pq^{\frac{7}{3}}}{p^{4}}        Dividing exponents with same base

=12p^{(1-4)}q^{\frac{7}{3}}        Subtract the exponent of 'p'

=12p^{(-3)}q^{\frac{7}{3}}        Negative exponent rule

=\frac{12q^{\frac{7}{3}}}{p^{3}}        Final answer

Here is a version in pen if the steps are hard to see.

5 0
3 years ago
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