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3 years ago

In electrical work, resistance is often represented by the

Physics

2 answers:

vova2212 [387]3 years ago

7 0

Answer : The correct option is, (a) Greek symbol O

Explanation :

Resistance : It is defined as the property of a material which resist the flow of charges through it.

Resistance is represented as, Ohm, $\Omega$ (in symbol) and uppercase Omega (in Greek symbol).

Hence, in electrical work, resistance is often represented by the Greek symbol O.

motikmotik3 years ago

3 0

In electrical work, resistance is often represented by the Greek symbol <span>Ω. The correct option among all the options that are given in the question is the first option or option "a". It is actually a Greek Letter Omega and is written in upper case. I hope this is the answer you were looking for and it has helped you.</span>

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One barometer tube has twice the cross-sectional area of another. mercury in the smaller tube will rise _____.

Andreas93 [3]

The answer is "the same than the mercury in the bigger tube".

If one barometer tube has twice the cross-sectional area of another, mercury in the smaller tube will rise the same than the mercury in the bigger tube.

The mercury will rise to the point where the column of mercury has the same weight as the force exerted by the atmosphere.

The force exerted by the atmosphere is pressure * cross-sectional area

Anf the weight of the column of mercury, W, will be:

W = m* g

where m = density * volume, and volume = cross-sectional area * height

=> W = density * cross-sectional area * height

Then, you make W = F and get:

density * cross-sectional area * height = P * cross-sectional area

The term cress-sectional area appears on both sides so it gets cancelled, and the height of the column of mercury does not depend on the cross-sectional area of the barometer.

4 0

3 years ago

Read 2 more answers

Beginning 145 miles directly south of the city of Hartville, a car travels due west. If the car is travelling at a speed of 42 m

ziro4ka [17]

Answer:

The rate of change of the distance is 14.89.

Explanation:

Given that,

Distance = 145 miles

Speed of car = 42 miles/hr

Distance covered by car = 55 miles

We need to calculate the the rate of change of the distance

According to figure,

Let OA is x, and AB is y.

Now, using Pythagorean theorem

$x^2=y^2+145^2$

On differentiating

$2x\dfrac{dx}{dt}=2y\dfrac{dy}{dt}$

$\dfrac{dx}{dt}=\dfrac{y}{x}\dfrac{dy}{dt}$

$\dfrac{dx}{dt}=\dfrac{55\times42}{\sqrt{55^2+145^2}}$

$\dfrac{dx}{dt}=14.89\ miles/hr$

Hence, The rate of change of the distance is 14.89.

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4 years ago

In the Fresnel circular aperture setup, the distances from the aperture to the light source and the reception screen are 1.5 m a

ivanzaharov [21]

Explanation:

The width of the central maximum is given by

W = 2 λ L / a

where W is the width of the central maximum

λ is the wavelength of the light used.

L is the distance between the aperture and screen

a is the width of the slit or aperture

So we can see that if any one quantity is varied by keeping others constant in the above formula , there would be a change in width of central maximum.

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3 years ago

Which of the following is an element

Ilia_Sergeevich [38]

D oxygen i believe is your answer

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4 years ago

An artificial satellite circles Earth in a circular orbit at a location where the acceleration due to gravity is 9.00 m/s2. Dete

Ksju [112]

<span>g = GMe/Re^2, where Re = Radius of earth (6360km), G = 6.67x10^-11 Nm^2/kg^2, and Me = Mass of earth. On the earth's surface, g = 9.81 m/s^2, so the radius of your orbit is:

R = Re * sqrt (9.81 m/s^2 / 9.00 m/s^2) = 6640km

here, the speed of the satellite is:

v = sqrt(R*9.00m/s^2) = 7730 m/s

the time it would take the satellite to complete one full rotation is:

T = 2*pi*R/v = 5397 s * 1h/3600s = 1.50 h

Hope it help i know it's long and may be confusing but if you have any more questions regarding this topic just hmu! :)</span>

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3 years ago