Log of 2x cube - log x = log 16 +log x
Use the identities!
Log 2x square = log 16x
2x square = 16 x
2x sqr - 16x = 0
2x(x-8) = 0
X = 0 or 8
According to logarithms x can’t be 0 so it’s 8
5 is d and idk question 5 sorry
We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula
we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3
log3(a/3)=[log (a/3)]/[log (3)]
the answer is
[log (a/3)]/[log (3)]
Convert to:
42 4 168
---- x ---- = ------
1 7 7
