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sp2606 [1]
2 years ago
6

The 100th term of 9​, 93​, 95​, 97​, ...

Mathematics
1 answer:
12345 [234]2 years ago
5 0

Answer:

207

Step-by-step explanation:

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> Question A normal distribution is observed from the number of points per game for a certain basketball player. If the mean
densk [106]

Answer:

The probability that in a randomly selected game, the player scored greater than 24 points is 0.0013 or 0.13%

Step-by-step explanation:

Given that

Mean = μ = 15 points

SD = σ = 3 points

For calculating probability for a data point, first of all we have to calculate the z-score of the value.

We have to find the probability of score greater than 24, then the z-score of 24 is:

z-score = (x-μ)/σ

z = (24-15)/3

z = 9/3

z = 3

Now we have to use the z-score table to find the probability of z<3 then it will be subtracted from 1 to find the probability of z>3

So,

P(z3) = 1 - P(z

Converting into percentage

0.0013 * 100 = 0.13%

Hence,

The probability that in a randomly selected game, the player scored greater than 24 points is 0.0013 or 0.13%

8 0
2 years ago
Solve for x: 2 over 3 (x − 4) = 2x
brilliants [131]
X = 7 just got it though Symbolab

8 0
3 years ago
2x + y = 4<br> 3x - y = 6
MrMuchimi

y=(1/2)x-1

You have to set both to y and then add. After that you solve for y

8 0
3 years ago
Read 2 more answers
Brainliest please help! A storage bin is a rectangular prism. Its volume is 300 cm cubed.
melisa1 [442]

Answer:

∛50 cm, 2∛50 cm, 3∛50 cm

Step-by-step explanation:

V= wlh

V=300 cm³

w= 1/3l

h= 2/3l

---------

  • l*1/3l*2/3l=300
  • 2/9l³=300
  • l³= 1350
  • l= ∛1350= 3∛50 cm
  • w= 1/3*3∛50= ∛50 cm
  • h= 2/3*3∛50= 2∛50 cm
6 0
3 years ago
Read 2 more answers
Slope-rate of change- “if there were 12,000 in the Atlantic Ocean in 1950 and there are 3,600 dolphins today, what is the yearly
jasenka [17]

\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{x}{year}&\stackrel{y}{dolphins}\\ \cline{1-2} &\\ 1950&12000\\ 2018&3600 \\&\\ \cline{1-2} \end{array}~\hspace{5em}(\stackrel{x_1}{1950}~,~\stackrel{y_1}{12000})\qquad (\stackrel{x_2}{2018}~,~\stackrel{y_2}{3600}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3600-12000}{2018-1950}\implies \cfrac{-8400}{68}~~\approx~~ \stackrel{\textit{rate of change}}{-123.53}


-8400/68 simplifies to to -2100/17,  dolphins/year, so 2100 less dolphins every 17 years.

and we can just divide those to get the decimal amount of -123.53, which means, 123.53  less dolphins every year.

of course, there's no such a thing as 0.53 of a dolphin, so, we can say "about" 123 less dolphins per year.

5 0
2 years ago
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