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Paul [167]
3 years ago
13

What error occurs when you perform an illegal math operation such as divide by zero

Computers and Technology
1 answer:
ch4aika [34]3 years ago
7 0

the answer is Arithmetic Exception error

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Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has
Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {    

   // declaration and initialization of integer variables

   int k, memberID = 12, nMembers=5;

   bool isAMember;    

   // declaration and initialization of integer array

   int currentMembers[] = {12, 34, 56, 78, 90};    

   for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           // when member is found in the array, the loop is exited using break

           isAMember = true;

           break;

       }

       else

           isAMember = false;

   }    

   return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using  a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           isAMember = true;

           break;

       }

       else

           isAMember = false;

 }

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

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“What does it mean when we “rework” copyrighted material?”
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Write a program that generates 1,000 random integers between 0 and 9 and displays the count for each number. (Hint: Use a list o
masya89 [10]

Answer:

import random

count0, count1, count2, count3,

count4, count5, count6, count7,

count8, count9, i = [0 for _ in range(11)]

while i < 1000:

   number = random.randint(0,9)

   if number == 0:

       count0 = count0 + 1

   if number == 1:

       count1 = count1 + 1

   if number == 2:

       count2 = count2 + 1

   if number == 3:

       count3 = count3 + 1

   if number == 4:

       count4 = count4 + 1

   if number == 0:

       count5 = count5 + 1

   if number == 6:

       count6 = count6 + 1

   if number == 7:

       count7 = count7 + 1

   if number == 0:

       count8 = count8 + 1

   if number == 9:

       count9 = count9 + 1

   

   i = i+1

print("0's: "+ str(count0) + "\n"+ "1's: "+ str(count1) + "\n"+

"2's: "+ str(count2) + "\n"+ "3's: "+ str(count3) + "\n"+

"4's: "+ str(count4) + "\n"+ "5's: "+ str(count5) + "\n"+

"6's: "+ str(count6) + "\n"+ "7's: "+ str(count7) + "\n"+

"8's: "+ str(count8) + "\n"+ "9's: "+ str(count9) + "\n")

Explanation:

- Initialize variables to hold the count for each number

- Initialize <em>i</em> to control the while loop

- Inside the while loop, check for the numbers and increment the count values when matched.

- Print the result

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