Question

∠1, ∠2, and ∠3 form a straight line. If m∠3 is six more than twice m∠1 and m∠2 is 27 less than m∠3, find m∠2.

Answer 1

Answer:

m<2 = 57

Step-by-step explanation:

Since they are all in a straight line, the sum of the three angles = 180

Let m ∠3 = x

Thus;

2m<1 = x - 6

m<1 = (x-6)/2

m<2 = x-27

Adding all

x + x-27 + (x-6)/2 = 180

Multiply through by 2

2x + 2x -54 + x -6 = 360

5x -60 = 360

5x = 360 + 60

5x = 420

x = 420/5

x = 84

But m<2 = x -27

m<2 = 84 -27 = 57