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baherus [9]
3 years ago
9

Find the volume of the hemisphere in the figure. Use the volume formula and 3.14 for π .

Mathematics
1 answer:
sergejj [24]3 years ago
5 0
Formula for a sphere is V = (4 ⁄ 3) π r^3

The picture shown showed the diameter.

Half of a diameter is the radius.

The radius is 2.95 yd.

Let’s plug in the values into the formula.

V = (4/3) 3.14 (2.95)^3

V = 107.48

NOW THATS THE ANSWER FOR A WHOLE SPHERE BUT YOURE LOOKING FOR THE HEMISPHERE.

So let’s divide that in half:

107.48/2 = 53.74

Your answer is B.) 53.74 yd
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HELP PLZZ Select the correct answer.
stira [4]

Answer:

none

Step-by-step explanation:

There is not a given angle side angle or a side angle side (no two angles and no two sides) so no to the first two.

HL includes two given side, which one must be the hypotenuse, and a right angle so no to that one.

6 0
2 years ago
Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

5 0
3 years ago
What is the value of x?<br> 33<br> 65<br> C=?
loris [4]

Answer:

56

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Arlecino [84]

Answer:

  A.  3.66 feet

Step-by-step explanation:

Using trigonometry, we know that ...

  BC = DC·tan(30°)

  AC = DC·tan(45°)

  AB = AC -BC = DC(tan(45°) -tan(30°))

  AB = 5√3·(1 -√3/3) = 5(√3 -1)

  AB ≈ 3.66 . . . feet

8 0
3 years ago
Kenny bought a new car stereo that cost $220, but he had a coupon for a 14% discount. How much did Kenny pay for the car stereo.
jok3333 [9.3K]

Answer:

189,2$

Step-by-step explanation:

220*0,86=189,2

14% = 14/100 = 0,14

1-0,14 = 0,86

price* factor between 0 and 1, 0 -> item is free, 1 -> full price

7 0
2 years ago
Read 2 more answers
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