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Ksivusya [100]
4 years ago
7

Independent: The value of an automobile bought in 2006 continues to decrease as time passes. This is

Mathematics
1 answer:
yarga [219]4 years ago
3 0

So we have this data:

- After 2 years, it's worth 17500$

- After 4 years, it's worth 14800$

Let's see how much decreases per year:

4 - 2 = 2 years difference

17500 - 14800 = 2700$ difference

2700$ / 2y =<em> </em><em>1350$/y</em> <em>(amount the value of the car decreases per year)</em>

<em />

Now we find how much it was worth at the beginning, for this we add 1350$ twice (for the 2 years) to 17500 (the amount it was worth 2 years after it was bought):

17500 + 2 * 1350 = 20200$

Our equation, then:

<em>Y = 20200 - 1350X</em>

For 2012 (6 years after 2006, the year it was bought):

Y = 20200 - 1350 * 6 = 20200 - 8100 = <em>12100$</em>

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\underline{\bf{Given \:equation:-}}

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