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chubhunter [2.5K]
3 years ago
7

How many bonds are present in Cl20?

Chemistry
1 answer:
DaniilM [7]3 years ago
4 0

Answer:

covalent bond, they are three

You might be interested in
XeF6 <br><br> formula mass =<br><br> molar mass =
Gemiola [76]

Answer:

Xenon hexafluoride's molar mass is about 245.28 g/mol
Formula mass is about 245.28 u.

Explanation:

So we want to find the formula mass of the XeF6 and there is a special formula for that.

You have to multiply the number of each element in XeF6 by the element's atomic mass.

The atomic mass of Xe is 131.293, and F's atomic mass is multiplied by 6, due to the 6 at the bottom. F's atomic mass is 18.998403, so we multiply the atomic number by 6, which would equal 113.990418. Round if you want, but it would equal mostly the same thing. Add it up to get ≈245.28, which is the same thing.

Therefore the formula mass of XeF6 is 245.28 u.

4 0
2 years ago
Consider the reaction below to answer the following question: This reaction is an example of: A. A Michael reaction B. A Robinso
Anestetic [448]

The reaction is missing, so i have attached it.

Answer:

C. An intramolecular aldol condensation

Explanation:

From the attached image showing the reaction, we can see that the left hand side of the reaction has 2 carbonyl groups which are the double bonds attached to the oxygen atoms.

Now, on the right hand side, we can see that a six member ring has been formed.

This 6 member ring is produced because one of the carbonyls on the left hand side was deprotonated at the alpha position thereby serving as a nucleophile, which then attacks the carbon in the other carbonyl.

This process is possible because it underwent the processes of deprotonation, intramolecular aldol addition, proton transfer and elimination to yield the right hand side product which is ɑ,β-unsaturated carbonyl compound.

Thus, the correct answer is option C

4 0
3 years ago
What is the wavelength, in nanometers, of light with a frequency of 1.97x10^15 Hz?
Iteru [2.4K]
*v=c/λ
λ = 3*10^8 m/s /1.97 *10^15
λ = 1.5 *10^-7
The calculated wavelength is in unit of meter. use the relationship between meter and nanometer to convert to the correct units.
4 0
2 years ago
What does this symbol, 1/0N, mean?
Firdavs [7]

An element can be represented symbolically in terms of its atomic number and mass number as:

_{Z}^{A}\textrm{X}

where X = symbol of the element

A = atomic mass

Z = atomic number

In this case we have the representation as:

_{0}^{1}\textrm{n}

where n = symbol for neutron

mass number of neutron = 1

charge/atomic number of neutron = 0

Ans: D) A neutron of zero charge and one unit mass



5 0
3 years ago
Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

8,040  

0.0300  

699.5  

2.000 x 102

0.90100  

90, 100  

4.7 x 10-8  

10,800,000.0  

3.01 x 1021

0.000410

Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

4) 2.000 x 10²

2.000 x 10²

Location is 4 and bar is over 0. This is because the number is decimal so trailing zeroes cannot be ignored. Also if we convert this number it becomes:

200.0 so last significant digit is 0 and location of last significant digit is 4.

5) 0.90100

0.90100

Location is 5 and bar is over 0. This is because in a number with decimal point starting zeroes are ignored but trailing zeroes after decimal point are not ignored. So we count from 9 and last significant digit is 0.

6) 90, 100

90, 100

Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

4.7 x 10⁻⁸

Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

4.7 x 10⁻⁸ =    0.000000047 = 0.000000047

Here the starting zeroes are ignored because there is a decimal point in the number.

8) 10,800,000.0

10,800,000.0

Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

9) 3.01 x 10²¹

3.01 x 10²¹

Location is 3 and bar is over 1. Lets expand this number first

3.01 x 10²¹ = 3.01 x 1000000000000000000000

                  = 3010000000000000000000

So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

10) 0.000410

0.000410

Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

6 0
3 years ago
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