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White raven [17]
3 years ago
12

Which of the following are correctly paired?

Chemistry
2 answers:
mart [117]3 years ago
8 0
Where’s the question tho?
spin [16.1K]3 years ago
8 0

Answer:

Watergirl and Fireboy

Explanation:

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A student finds two unlabeled flasks of clear liquids. One is believed to be 0.1 m nacl and the other to be 0.1 m naclo3. What i
KonstantinChe [14]

Answer:

  • Add AgNO₃ solution to both unlabeled flasks: based on solubility rules, you can predict that when you add AgNO₃ to the NaCl solution, you will obtain AgCl precipitate, while no precipitate will be formed from the NaClO₃ solution.

Explanation:

<u>1. Adding AgNO₃ to NaCl solution:</u>

  • AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

<u>2. Adding AgNO₃ to NaClO₃ solution</u>

  • AgNO₃ (aq) + NaClO₃ (aq) → AgClO₃ (aq) + NaNO₃ (aq)

<u />

<u>3. Relevant solubility rules for the problem.</u>

  • Although most salts containing Cl⁻ are soluble, AgCl is a remarkable exception and is insoluble.

  • All chlorates are soluble, so AgClO₃ is soluble.

  • Salts containing nitrate ion (NO₃⁻) are generally soluble and NaNO₃ is not an exception to this rule. In fact, NaNO₃ is very well known to be soluble.

Hence, when you add AgNO₃ to the NaCl solution the AgCl formed will precipitate, and when you add the same salt (AgNO₃) to the AgClO₃ solution both formed salts AgClO₃ and NaNO₃ are soluble.

Then, the precipiate will permit to conclude which flask contains AgCl.

6 0
3 years ago
Name of SiO3? Please hurry lol
BartSMP [9]
The name that I found is Silicate
7 0
3 years ago
You have 846 ml of 3.95 M HCl. Using a volumetric pipet, you take 268 ml of that solution and dilute it to 803 ml in a volumetri
Anettt [7]

Answer: The concentration of hydrochloric acid in the final solution is 0.72 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 3.95 M

V_1 = volume of stock solution = 268 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 803 ml

3.95\times 268=M_2\times 803

M_2=1.32M

Next, you take 100.00 ml of that solution and dilute it to 184 ml in a volumetric flask.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.32 M

V_1 = volume of stock solution = 100 ml

M_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 184 ml

1.32\times 100=M_2\times 184

M_2=0.72M

Thus concentration of hydrochloric acid in the final solution is 0.72 M

7 0
3 years ago
Given the reaction:
dezoksy [38]

Answer:

V = 22.34 L

Explanation:

Given data:

Volume of O₂ needed = ?

Temperature and pressure = standard

Number of molecules of water produced = 6.0× 10²³

Solution:

Chemical equation:

2H₂ + O₂       →      2H₂O

Number of moles of water:

1 mole contain 6.022× 10²³ molecules

6.0× 10²³ molecules ×  1 mole  /  6.022× 10²³ molecules

0.99 mole

Now we will compare the moles of oxygen and water.

                  H₂O         :            O₂  

                    2            :              1

               0.996         :          0.996

Volume of oxygen needed:

PV = nRT

V = nRT/P

V = 0.996 mol × 0.0821 atm.L/mol.K ×  273.15 K / 1 atm

V = 22.34 L

3 0
3 years ago
What are three possible problems with storing low level nuclear waste?​
ella [17]

Answer:

Diarrhea may caused

flies in the home which transfer germs

Kat one think your self

3 0
3 years ago
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