Here we have to calculate the number of moles of valuable propane can be prepared from 1.8 moles of carbon.
From 1.8 moles of carbon 0.3 moles of propane can be prepared by the reaction.
From 6 moles of carbon (C) 1 moles of valuable propane (C₃H₈) can be prepared.
Thus from 1.8 moles of C we can obtain ×1.8 = 0.3 moles of the propane can be prepared.
Thus the amount of propane produced in this reaction is determined.
Answer:
<h3>The answer is 3 g/cm³</h3>Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>3 g/cm³</h3>Hope this helps you
Answer:
See explaination
Explanation:
The mole balance for a constant-volume batch reactor is given such as, For a first-order isothermal reaction, the time to reach a given conversion is the same for constant-pressure and constant-volume reactors. Also, the time is the same for a reaction of any order if there is no change in the number of moles.
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