The correct answer is C. Side “a” is always longer than side “b”.
Volume of a cylinder is h x r^2 x pi
You have the volume and radius of each one, so taking 188.4=(2)^2 x 3.14 x h1, you can solve this equation for the height h1. Likewise, for the other graduated cylinder you take 314=2^2 x 3.14 x h2, and then solve for h2.
To get the difference in heights, just take h2-h1 after solving the equations for h2 and h1
Answer:
Hey, welcome to Brainly ACD is a straight line. Angle CAB = 50°. Angle ABC = 60°. Work out the size of the angle marked x. Hope this helps.
Step-by-step explanation:
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Answer:
<h2>length= 40cm</h2><h2>width= 120cm</h2><h2>
Step-by-step explanation:</h2>
Area of a rectangle= lenght× width
Dimensions of 1st rectangle: L,W
Dimensions of 2nd rectangle: L+10; W+4
Hence,
LW = 480__________(1)
(L-10)(W+4) = 480_______(2)
LW = LW+4L - 10W - 40
4L = 10W +40
2L = 5W + 20
L = (5/2)W + 10_________(3)
But LW = 480 (from equation one)
So, W = 480/L
substitute as= 480/L into equation (3)
L = (5/2)(480/L)+10
L = 1200/L + 10
L^2 - 10L - 1200 = 0
factorising.
we're have,
(L-40)(L+30) = 0
therefore, since L can't be negative , L = 40
L = 40 cm (length)
Then 480/L = W = 120 cm (width)
<h2>therefore L= 40cm and W= 120cm</h2>
