Find the product of (x – a) and (x

A recipe for oatmeal raisin cookies calls for 1 2/3 cups of flour to make 4 dozen cookies .how many cups of flour are needed to

erastovalidia [21]

$2 \frac{1}{2}$

4 0

3 years ago

Find the p-value: An independent random sample is selected from an approximately normal population with an unknown standard devi

vladimir1956 [14]

Answer:

(a) p-value = 0.043. Null hypothesis is rejected.

(b) p-value = 0.001. Null hypothesis is rejected.

(c) p-value = 0.444. Null hypothesis is not rejected.

(d) p-value = 0.022. Null hypothesis is rejected.

Step-by-step explanation:

To test for the significance of the population mean from a Normal population with unknown population standard deviation a t-test for single mean is used.

The significance level for the test is α = 0.05.

The decision rule is:

If the p - value is less than the significance level then the null hypothesis will be rejected. And if the p-value is more than the value of α then the null hypothesis will not be rejected.

(a)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 11.

The test statistic value is, t = 1.91 ≈ 1.90.

The degrees of freedom is, (n - 1) = 11 - 1 = 10.

Use a t-table t compute the p-value.

For the test statistic value of 1.90 and degrees of freedom 10 the p-value is:

The p-value is:

P (t₁₀ > 1.91) = 0.043.

The p-value = 0.043 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(b)

The alternate hypothesis is:

Hₐ: μ < μ₀

The sample size is, n = 17.

The test statistic value is, t = -3.45 ≈ 3.50.

The degrees of freedom is, (n - 1) = 17 - 1 = 16.

Use a t-table t compute the p-value.

For the test statistic value of -3.50 and degrees of freedom 16 the p-value is:

The p-value is:

P (t₁₆ < -3.50) = P (t₁₆ > 3.50) = 0.001.

The p-value = 0.001 < α = 0.05.

The null hypothesis is rejected at 5% level of significance.

(c)

The alternate hypothesis is:

Hₐ: μ ≠ μ₀

The sample size is, n = 7.

The test statistic value is, t = 0.83 ≈ 0.82.

The degrees of freedom is, (n - 1) = 7 - 1 = 6.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₆ < -0.82) + P (t₆ > 0.82) = 2 P (t₆ > 0.82) = 0.444.

The p-value = 0.444 > α = 0.05.

The null hypothesis is not rejected at 5% level of significance.

(d)

The alternate hypothesis is:

Hₐ: μ > μ₀

The sample size is, n = 28.

The test statistic value is, t = 2.13 ≈ 2.12.

The degrees of freedom is, (n - 1) = 28 - 1 = 27.

Use a t-table t compute the p-value.

For the test statistic value of 0.82 and degrees of freedom 6 the p-value is:

The p-value is:

P (t₂₇ > 2.12) = 0.022.

The p-value = 0.444 > α = 0.05.

The null hypothesis is rejected at 5% level of significance.

5 0

3 years ago

Given that P = (2, 9) and Q = (4, 14), find the component form and magnitude of vector PQ.

vredina [299]

The magnitude of the vector is
$\sqrt{2 {}^{2} + 5 {}^{2} } = \sqrt{29}$
the component form is
<2,5>

8 0

3 years ago

Read 2 more answers

Emily Dickinson's poetry was rescued for posterity by

LiRa [457]

Emily Dickinson's poetry was rescued for posterity by her sister (c). Emily Dickinson lived during the American Civil War, but she lived in her father's house in Amherst, Massachusetts. This area was not affected by the Civil War. She was fairly isolated as a poet and, as a result, the events of the Civil War did not play a major role in her poetry. She wrote mainly about the events in her direct environment, with no direct sense of the time in which she lived. Her world consisted of her own home and the surrounding countryside.

6 0

3 years ago

Using the rules for special cases, what is the result of?

Arlecino [84]

Answer:

C) 4x^2 -8x +4[/tex]

Step-by-step explanation:

(-2x+2)^2

we apply (a+b)^2 formula

$(a+b)^2 = a^2 + 2ab +b^2$