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bija089 [108]
3 years ago
7

For the functions f left parenthesis x right parenthesis equals 6 minus x squared and g left parenthesis x right parenthesis equ

als x squared plus 4 x minus 12​, find fplus​g, fminus​g, ​fg, and StartFraction f Over g EndFraction . Determine the domain for each function.
Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

Step-by-step explanation:

Given the functions

F(x) = 6-x²

G(x) = x²+4x-12

A) we are to find F(x)+g(x)

F(x)+G(x) = 6-x²+x²+4x-12

F(x)+G(x) = 6+0+4x-12

F(x)+G(x) = 4x+6-12

F(x)+G(x) = 4x-6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

F(x)-g(x) = 6-x²-(x²+4x-12)

F(x)-g(x) = 6-x²-x²-4x+12

F(x)-g(x) = 6-2x²+4x+12

F(x)-g(x) = -2x²+4x+6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

3) F(x)/G(x)

= 6-x²/x²+4x-12

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

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Now, y = 3^{x-4} is a child of the parent function we just described. Precisely, it is the result of the transformation f(x) \to f(x-4)

In general, every time you perform a transformation like f(x) \to f(x+k), you translate the graph horizontall, k units to the left if k is positive, and k units to the right if k in negative.

Since in this case k = - 4, we have a horizontal translation of 4 units to the right.

So, the correct option is the third one, because:

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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Answer:

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After that, you keep the first fraction, flip the sign and the fraction.

You will get: 5/9 multiplied by 3/2.

When you get this, you then cross multiply and simplify as such.

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5/6 would be your solution.

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