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bija089 [108]
3 years ago
7

For the functions f left parenthesis x right parenthesis equals 6 minus x squared and g left parenthesis x right parenthesis equ

als x squared plus 4 x minus 12​, find fplus​g, fminus​g, ​fg, and StartFraction f Over g EndFraction . Determine the domain for each function.
Mathematics
1 answer:
Ksju [112]3 years ago
8 0

Answer:

Step-by-step explanation:

Given the functions

F(x) = 6-x²

G(x) = x²+4x-12

A) we are to find F(x)+g(x)

F(x)+G(x) = 6-x²+x²+4x-12

F(x)+G(x) = 6+0+4x-12

F(x)+G(x) = 4x+6-12

F(x)+G(x) = 4x-6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

F(x)-g(x) = 6-x²-(x²+4x-12)

F(x)-g(x) = 6-x²-x²-4x+12

F(x)-g(x) = 6-2x²+4x+12

F(x)-g(x) = -2x²+4x+6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

3) F(x)/G(x)

= 6-x²/x²+4x-12

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

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Make B the subject of the relation : 1/a is equal to 1/b + c​
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By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

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1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]

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This will not work if c = -b, because then you would be dividing by zero.

Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6

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in wereda election where four candidates appeared for election, the winning candidate received 36,000 votes which represented 45
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Let's see

Total votes be x

  • 45% of x=3600
  • 0.45x=3600
  • x=3600/0.45
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Now total percentage of vote

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Not voted=4%

Find not voted

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Total voted

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7 0
1 year ago
Read 2 more answers
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