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bija089 [108]
4 years ago
7

For the functions f left parenthesis x right parenthesis equals 6 minus x squared and g left parenthesis x right parenthesis equ

als x squared plus 4 x minus 12​, find fplus​g, fminus​g, ​fg, and StartFraction f Over g EndFraction . Determine the domain for each function.
Mathematics
1 answer:
Ksju [112]4 years ago
8 0

Answer:

Step-by-step explanation:

Given the functions

F(x) = 6-x²

G(x) = x²+4x-12

A) we are to find F(x)+g(x)

F(x)+G(x) = 6-x²+x²+4x-12

F(x)+G(x) = 6+0+4x-12

F(x)+G(x) = 4x+6-12

F(x)+G(x) = 4x-6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

F(x)-g(x) = 6-x²-(x²+4x-12)

F(x)-g(x) = 6-x²-x²-4x+12

F(x)-g(x) = 6-2x²+4x+12

F(x)-g(x) = -2x²+4x+6

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

3) F(x)/G(x)

= 6-x²/x²+4x-12

The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER

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Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
inn [45]

Complete Question

Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)  

t=8.169  

P-value= ?

Answer:

a)  P-value=0

b)  Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

Step-by-step explanation:

From the question we are told that:

Sample size n=10

Mean \=x= 51.3

Standard deviation \sigma=1.2

Significance level is taken as \alpha=0.05

t test statistics

t=8.169

Therefore

P-Value=P(t>8.169)

Critical point

t_{\alpha,df}

\alpha=0.05

df=10-1=>9

Therefore

P-value from T distribution table

P-value=0

Conclusion

P-value (0)< \alpha(0.05)

We Reject the Null Hypothesis H_0

Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/  cellulose composite exceeds 48 MPa.

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Determine la pendiente (m) de la recta que pasa por los puntos (2,3) y (- 2, - 4
labwork [276]
La pendiente de la recta que pasa por los puntos (2,3) y (-2,-4) es 7/4.

(2,3)      (-2,-4)
x₁ y₁       x₂  y₂

                y₂ - y₁       -4 -3           -7            7
              ----------- = --------- = ----------- = ------
                x₂ - x₁      -2 - 2           -4            4
                    ↑

                    ↑
la fórmula de el pendiente





5 0
4 years ago
30 miles in 4 hours in simplest form
SIZIF [17.4K]

Answer:

<u>15/2</u>

Step-by-step explanation:

  1. 30/4=7.5
  2. convert the decimal to a fraction
  3. 7.5 would give you 15/2 in fraction form
  4. since you can't simplify 15/2 anymore, <u>15/2</u> would be your answer.
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