Answer:
Step-by-step explanation:
Given the functions
F(x) = 6-x²
G(x) = x²+4x-12
A) we are to find F(x)+g(x)
F(x)+G(x) = 6-x²+x²+4x-12
F(x)+G(x) = 6+0+4x-12
F(x)+G(x) = 4x+6-12
F(x)+G(x) = 4x-6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
F(x)-g(x) = 6-x²-(x²+4x-12)
F(x)-g(x) = 6-x²-x²-4x+12
F(x)-g(x) = 6-2x²+4x+12
F(x)-g(x) = -2x²+4x+6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
3) F(x)/G(x)
= 6-x²/x²+4x-12
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
