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PSYCHO15rus [73]
3 years ago
15

Is(5, 6)asolutiontotheinequality y < 2x + 4 ?

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

Substitute the values.

x = 5

y = 6

y < 2x + 4

6 < 2(5) + 4

6 < 10 + 4

6 < 14

6 is indeed less than 14

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How is using a double number line similar to finding equivalent ratios?
Karolina [17]
One way that double number lines are similar to finding equivalent ratios is that to find your answer on a double number line, you add equivalent ratios to your number line.
4 0
3 years ago
What is the 7th term of the sequence 3,12,48,192
Sedbober [7]
If you look at this sequence, every term of this sequence is being multiplied by 4.

3 x 4 = 12
12 x 4 = 48
48 x 4 = 192
192 x 4= 768
768 x 4 = 3072
3072 x 4 = 12288

So the 7th term of this sequence is 12288.
8 0
3 years ago
PLEASE TAP ON THE PHOTO I NEED HELP ASAP
d1i1m1o1n [39]

5, 3, -5, -1

-2x-1 = 2+3= 5

-2x0 = 0+3= 3

-2x1 = -2+3= -5

-2x2 = -4+3= -1

5 0
3 years ago
Evaluate the expression (3-2i)(3-2i) and write the result in the form a+bi ,where a is the real part of your answer and bis the
Maslowich

Answer:

a = 5, b = -12

Step-by-step explanation:

By basic factoring, you get 9 - 12i + 4i^2. Since i^2 is simply -1, the expression evaluates to 9 - 12i - 4, which is 5 - 12i.

4 0
2 years ago
Benny is trying to learn how to ride a bike, but is terrified of falling. He did some research, and discovered that if he rides
Anestetic [448]

Answer:

a) 7.14% probability that Benny was learning to ride a bike using the training wheels

b) 28% probability that Benny was learning to ride a bike using the training wheels

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

Benny came home crying with a bruise on his knee, after falling. His mom is trying to guess how Benny was trying to learn to ride a bike.

a) Assuming that the probability that Benny was using each of these 3 methods is equal, what is the probability that Benny was learning to ride a bike using the training wheels?

So

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that Benny was using each of these 3 methods is equal

This means that P(B) = \frac{1}{3}

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

1/3 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

1/3 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

1/3 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = \frac{0.1 + 0.5 + 0.8}{3} = 0.4667

So

P(B|A) = \frac{\frac{1}{3}*0.1}{0.4667} = 0.0714

7.14% probability that Benny was learning to ride a bike using the training wheels

b) Since Benny's mom knows Benny so well, she knows that the probability that he was using training wheels is 0.7, regular bike is 0.2, and unicycle is 0.1. What is the probability now that Benny fell while using the training wheels?

Similar as above, just some probabilities change.

Event A: Benny fell

Event B: Benny was using training wheels.

The probability that he was using training wheels is 0.7

This means that P(B) = 0.7

He did some research, and discovered that if he rides a bike with training wheels, the probability of falling is 0.1;

This means that P(A|B) = 0.1

Probability of falling:

0.7 of the time, he uses training wheels. With training wheels, the probability of falling is 0.1.

0.2 of the time, he uses the bike without training wheels. Without training wheels, the probability of falling is 0.5

0.1 of the time, he uses the unicycle, for which he has an 0.8 probability of falling. Then

P(A) = 0.7*0.1 + 0.2*0.5 + 0.1*0.8 = 0.25

So

P(B|A) = \frac{0.7*0.1}{0.25} = 0.28

28% probability that Benny was learning to ride a bike using the training wheels

7 0
4 years ago
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