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fredd [130]
3 years ago
7

Base:9.44 area=70.8 WHAT IS THE HIEGHT

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
6 0
Divide

a = b * h
we know the base and area, not height

h = a/b
h = 70.8/9.44
h = 7.5

Your height is 7.5 units 
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Mrs. Chip bought 2 sheets and a blanket and paid $41. Mrs. Dale bought a sheet and 4 blankets and paid $80.
Katyanochek1 [597]

Answer:

  • Sheet = $12
  • Blanket = $17

Step-by-step explanation:

<u>Let the cost of a sheet be s and cost of a blanket be b</u>

  • 2s + b = 41
  • s + 4b = 80

<u>From the first equation we get:</u>

  • b = 41 - 2s

<u>Substitute in the second equation</u>

  • s + 4*(41 - 2s) = 80
  • s + 164 - 8s =  80
  • 7s = 84
  • s = 12

<u>Then</u>

  • b = 41- 2*12 = 17
6 0
3 years ago
The price of a share of stock started the day at $37. During the day it went down $3, up $1, down $7 and up $4. What was the pri
Oksana_A [137]
It started at $37.

It went down $3.
37 - 3 = 34

It went up 1.
34 + 1 = 35

It went down 7.
35 - 7 = 28

It went up 4.
28 + 4 = 32

The price at the end of the day was $32.
4 0
3 years ago
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aliya0001 [1]
This is a function because each input has exactly one output ❤️
7 0
3 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
Answer quick for brainliest!
Step2247 [10]

Answer:

C (1,1) is another point on the line

6 0
3 years ago
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