$10,000 at 7% continuous compounding for 8 years
Answer: A
Base:9.44 area=70.8 WHAT IS THE HIEGHT
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Answer:
the null and alternative hypothesis are
: p=0.24
: p≠0.24
Test statistic is 1.416.
P-Value is 0.1568
We fail to reject the null hypothesis under 0.05 significance level
<em>At 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)
Step-by-step explanation:
Let p be the proportion of offspring peas will be yellow. Then,
: p=0.24
: p≠0.24
test statistic can be calculated as
z= where
- p(s) is the sample proportion of yellow offspring peas (
- p is the proportion of yellow offspring peas assumed under null hypothesis. (0.24)
- N is the sample size (585)
Test statistic is z= ≈ 1.416.
Using z-table, we can find that P-Value is 0.1568
We fail to reject the null hypothesis under 0.05 significance level since 0.157>0.05
We can conclude that <em>at 0.05 significance</em> we cannot say that the proportion of offspring peas will be yellow is not 0.24 (24%)