Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
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f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
Answer:
0
Step-by-step explanation:
7x + -2z = 4 + -1xy
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add 'xy' to each side of the equation.
7x + xy + -2z = 4 + -1xy + xy
Combine like terms: -1xy + xy = 0
7x + xy + -2z = 4 + 0
7x + xy + -2z = 4
Add '2z' to each side of the equation.
7x + xy + -2z + 2z = 4 + 2z
Combine like terms: -2z + 2z = 0
7x + xy + 0 = 4 + 2z
7x + xy = 4 + 2z
Reorder the terms:
-4 + 7x + xy + -2z = 4 + 2z + -4 + -2z
Reorder the terms:
-4 + 7x + xy + -2z = 4 + -4 + 2z + -2z
Combine like terms: 4 + -4 = 0
-4 + 7x + xy + -2z = 0 + 2z + -2z
-4 + 7x + xy + -2z = 2z + -2z
Combine like terms: 2z + -2z = 0
-4 + 7x + xy + -2z = 0
Yes the relation is a function no number repeat
