Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
No, because he only surveyed his class which 65% of them prefer planting corn over tomatoes. In which it does not mean that the school's third grade population that prefers planting corn over tomatoes is 65%
Answer:
1) 100 ) 15
Step-by-step explanation:
1) 30 to 50 is 20 miles so 5 * 20 is 100
2)20 to 50 is 30 miles so its 150 and 15 to 20 is 5 so 11 *5 is 55
55+150 equals 250 so the answer is 15 miles.
Answer:
211 cm
Step-by-step explanation:
upper rectangle + lower rectangle (11-8=3) + end triangles
(8x20) + (3x12) + (1/2x3x5 each x2)
160+36+15=211