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yanalaym [24]
2 years ago
5

If the area of the rectangle is 60 square inches, what is the width of the rectangle?

Mathematics
1 answer:
lesya692 [45]2 years ago
6 0

Answer:

put a picture up

Step-by-step explanation:

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ella [17]
The answer is 40 inches. Reason is a^2 + b^2 = c^2. A is 42. B is unknown. C is 58. Taking that information it is 40 inches
7 0
2 years ago
If you can answer these two questions you can get 15 points
irina1246 [14]

Answer:

formula is y= mx + c  (c=y intercept)

1) slope= m= -0.75, y intercept = -2

y= -0.75x - 2

-------------------------------------------------------------------

2)slope=m=0.5, y intercept = 8

y= 0.5x + 8

6 0
3 years ago
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Im distributive property and combining like term and I have to simplify this expression 10(7r)
faltersainse [42]
It would be 70r if you are using distributive property
8 0
3 years ago
One of the legs of a right triangle measures 4 cm and its hypotenuse measures 18 cm. Find the measure of the other leg. If neces
Aleks04 [339]

Answer:

√308 or 17.5

Step-by-step explanation:

c^2=a^2+b^2

c^2-a^2=b^2

Substitute

18^2-4^2=b^2

324-16=b^2

b^2=308

b=√308 or b=17.5

7 0
2 years ago
A poll asked 1057 American adults if they believe there was a conspiracy in the assassination of President Kennedy, and found th
AVprozaik [17]

Answer:

The 95% confidence interval of the proportion of Americans who believe in the conspiracy is  0.551<  p <  0.610

Step-by-step explanation:

From the question we are told that

   The sample size is  n =1057

   The number that believe there was a conspiracy is  k = 614

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{614}{1057 }

=>   \^ p = 0.5809

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E = 1.96 * \sqrt{\frac{0.5809 (1- 0.5809)}{1057} }    

=>   E = 0.02975  

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.5809 - 0.02975<  p <  0.5809 + 0.02975

=>    0.551<  p <  0.610

4 0
2 years ago
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