On desmos, a graphing calculator, I inputted your numbers, and I got that each side is 11 units long. Therefore, because a hexagon has 6 sides, you would have 6 * 11 = 66 units.
Therefore, your answer is 66.
Hope this helps and have a nice day:)
B: 2 and 1/6.
Tricky one if you rush through, its meant to SEEM complicated, like a lot of math questions.
Answer:
-3 i hope this helps :)
Step-by-step explanation:
(4,7) (7,-2)
x1 y1 x2 y2
<u>-2 - 7 </u> = <u>-9</u> = -3
7 - 4 3
Easy! 5×3 tickets which equals 15 tickets in all!
Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like
(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}
√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then
(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}
A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that
(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}
I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then
(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.
N is a subset of B, so
(iv.b) N - B = N = {1, 2, 3, ...}
