|a+bi| = √(a² + b²)
-4-√2 i -> take a = -4 and b = -√2
|-4-√2 i| = √[ (-4)² + (<span>-√2)² ]
= </span><span>√[ 16 + 2<span> ]
</span></span><span>= √[ 18 ]</span> = <span>√[ 9 * 2 ]
= 3√2
the absolute value is 3√2</span>
Answer:
A
Step-by-step explanation:
You take the 64 teams, split it in half, and then the exponent is r
The probability of getting a 2 or a getting a black card, find individual probabilities;
A standard deck has 52 cards.
There are 4 2's in a normal deck; probability of getting it is 4/25
The probability of getting a black card is; 26/52 since half the deck is red and black.
Now add up the probabilities since it says "or"
(4/52)+(26/52)=30/52 probability of the card that you were dealt being a two or a black card.
Hope I helped :)
Y - (-8) = -6 (x-2) is correct everything else is not
y + 8 = -6x + 12
y +:8 - 8 = -6x + 12 - 8
y = -6x + 4 is slope intercept form
Well you know you keep the 7. 1/3 well you see it as .3333 so just go 7.33 because 7.333 and since it's a 3 you keep it.
