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Amiraneli [1.4K]
3 years ago
8

Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable out

comes are there for choosing a multiple of 3?
Mathematics
1 answer:
Mice21 [21]3 years ago
8 0
<h3>If a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.</h3>

Step-by-step explanation:

The number of possible numbers on the tile are:

0, 1 , 2 , 3 , 4,  5,  6,  7 ,  8 and 9.

Now, the chosen tile can have any of the ten options mentioned above.

The favorable outcomes are  3 , 6 and 9 as they are the multiple of 3.

So, the number of possible favorable outcomes  = 3 ways

Hence, if a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

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