Answer:
60 mph
Step-by-step explanation:
Given;
Total distance covered d = 440 miles
Average speed in the first 4 hours v1 = 50 mph
Total time taken for the whole trip t = 8:00 to 4:00pm
t = 16:00-8:00 = 8 hours
Firstly we need to calculate the distance covered during the first 4 hours;
d1 = average speed × time = v1 × t1
t1 = 4
d1 = 50 × 4 = 200 miles
Then we need to calculate the distance covered in the second period of the journey;
d = d1 + d2
d2 = d - d1
Substituting the values;
d2 = 440 - 200
d2 = 240 miles
The time taken for the second period of travel t2;
t2 = t -t1 = 8-4
t2 = 4 hours
Average speed = distance travelled ÷ time taken
The average speed for the second part of the trip v2 is;
v2 = d2 ÷ t2
Substituting t2 and d2;
v2 = 240 miles ÷ 4 hours
v2 = 60 mph
The average speed during the second part of the trip is 60 mph
The 0 in the number 402 is in the ten place. The number after it is 2. 2 is less than 5.
402 rounded to the nearest ten is 400
The 4 in the number 402 is in the hundreds place. The number after it is 0. 0 is less than 5.
402 rounded to the nearest hundred is 400
I hope you want to simplify this expression.
To simplify the given expression we can use the order of operation.
So, first step is to operate multiplication. Therefore,
400 x 34 = 13600
Hence,
400x34+23444444444-23444444444
= 13600 +23444444444-23444444444
= 13600 + 0 Since +23444444444-23444444444 = 0
= 13600.
So, the simplified value of the given expression is 13600.
Hope this helps you!.
What’s your last question
2000+1200=3200=thirty two hundreds
