Ask question

Ask question

All categories

3 years ago

10

At a bake sale, students sold 3 muffins for every 8 cookies.the students sold 24 muffins altogether. how many cookies did they s

ell?

1 answer:

dsp733 years ago

3 0

64 Muffins

3:8
24:a

24/3 = y
y=8

a = 8 x y
a = 8 x 8
a = 64 muffins

You might be interested in

ABC ~ AYZ , what's the value of x?

aleksklad [387]

Answer:

Step-by-step explanation:

6cm

8 0

2 years ago

Which equation and solution represents the statement shown?

Vladimir79 [104]

Answer:

I believe the answer is

x + 4 = 6.5

-4 -4

__________

x = 2.5

Step-by-step explanation:

hope this helps!

6 0

2 years ago

Which of the following is a conjugate for 7 + i Square root of 2? (2 points) − 7 + i Square root of 2 7 − i Square root of 2 i S

hammer [34]

Answer:

$7-\sqrt{2}i$

Step-by-step explanation:

Given number is $7+\sqrt{2}i$ . We need to find the complex conjugate of the given number.

We will use the general rule to find out the complex conjugate of the number.

The complex conjugate of $a+bi$ will be $a-bi$

And the complex conjugate of $7+\sqrt{2}i\ became\ 7-\sqrt{2}i$

So, the complex conjugate of $7+\sqrt{2}i$ is $7-\sqrt{2}i$

3 0

3 years ago

Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)

borishaifa [10]

Answer:

Since,

$\frac{d}{dx}x^n = nx^{n-1}$

$\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))$

$\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}$

1) $y = 8x e^x$

Differentiating with respect to x,

$\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)$

2) $y = 5x e^{x^4}$

Differentiating w. r. t x,

$\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)$

3) $y = x^8 + \frac{5}{x^4}$

Differentiating w. r. t. x,

$\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}$

4) $f(t) = te^{11}-6t^5$

Differentiating w. r. t. t,

$f'(t) = e^{11} - 30t^4$

5) $g(p) = p\ln(2p+3)$

Differentiating w. r. t. p,

$g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)$

6) $z = (te^{6t}+e^{5t})^7$

Differentiating w. r. t. t,

$\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})$

7) $w =\frac{2y + y^2}{7+y}$

Differentiating w. r. t. y,

$\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}$

7 0

3 years ago

What is the value of the expression- -14+8-12

mojhsa [17]

-14+8=-6. -6-12=-18 ....................

7 0

2 years ago