Answer:
(x + 1 s 1) n (x + 12 1)
(x +1<1) n (x + 1 > 1)
Step-by-step explanation:
Just simplify each the statements.
Then compare and and see if the statements are contradictory and therefore FALSE, if so, then there is no solution.
(x + 1<-1) n (x + 1< 1)
(x <-2) n (x < 0) which is true, so there is a solution.
(x + 1 s 1) n (x + 12 1)
this doesn't make sense so there is no solution.
(x +1<1) n (x + 1 > 1)
(x < 0) n (x > 0)
This is not possible, the statements are contradictory and therefore FALSE, so there is no solution.
The simple interest accrued is = $750
<h3>Calculation of simple interest</h3>
The principal amount of the loan = $7500
The rate at which the interest is paid is = 2.5%
The time that it will take to pay the interest = 4 years
Using the formula for Simple interest;
SI= P×T×R/100
SI = 7500×4 × 2.5/100
SI= 75000/100
SI=$750
Therefore, the interest accrued on a $7500 loan with a 2.5% interest rate over 4 years is = $750
Learn more about simple interest here:
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Answer:



Step-by-step explanation:
We know that:
Only employees are hired during the first 3 days of the week with equal probability.
2 employees are selected at random.
So:
A. The probability that an employee has been hired on a Monday is:
.
If we call P(A) the probability that 2 employees have been hired on a Monday, then:

B. We now look for the probability that two selected employees have been hired on the same day of the week.
The probability that both are hired on a Monday, for example, we know is
. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.
So
.
C. If the probability that two people have been hired on a specific day of the week is
, then the probability that 7 people have been hired on the same day is:

D. The probability is
. This number is quite close to zero. Therefore it is an unlikely bastate event.
Given:
The graph of cost of taxi with respect to number of miles.
To find:
The formula for C in terms of n.
Solution:
In the given graph x axis represents the number of miles (n) and y-axis represents the cost of taxi (C).
From the given graph it is clear that, the line passes through the points (0,3) and (5,6). So, the equation of line is



Adding 3 on both sides, we get

Putting y=C and x=n, we get

Therefore, the required formula is
.
The possible solution is 12 cats and 4 dogs in Sarah's store.
Let x represent the number of cats and y represent the number of dogs.
Since Sarah's Pet Store never has more than a combined total of 16 cats and dogs. Hence:
Also, She also never has more than 9 cats. Therefore:
The solution to the inequality is graphed. From the graph, the possible solution is 12 cats and 4 dogs
Find out more on inequalities at: brainly.com/question/24372553