Answer:
a) Narrower
b) Narrower
c) Wider
Step-by-step explanation:
We are given the following in the question:
Proportion of coworker who received flu vaccine = 32%
98% confidence interval: (0.231, 0.409)
Confidence interval:
![\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D%5Cpm%20z_%7Bstat%7D%5Csqrt%7B%5Cdfrac%7B%5Chat%7Bp%7D%281-%5Chat%7Bp%7D%29%7D%7Bn%7D%7D)
a) Sample size had been 600 instead of 150
If we increase the sample size, thus the standard error of the interval decreases.
Since the standard error decreases, the confidence interval become narrower.
b) Confidence level had been 90% instead of 98%
As the confidence level increases, the confidence interval becomes narrower. This is due to a smaller value of z-statistic at 90% confidence level.
c) Confidence level had been 99% instead of 98%
As the confidence level increases, the width of the confidence interval increases and the confidence interval become wider. This is because of a larger value of z-statistic at 99% confidence interval.
8 choose 3 is 336. 336 is the answer
Answer:
- 20 - (3 × 23 - 5) =
- 20 - (69 - 5) =
- 20 - 64 =
- - 44
Note.
<em>The answer options are not matching the question. Something is wrong with the question.</em>
Answer:
86 %
Step-by-step explanation:
Total no. of squares = 50
No. of green squares = 43
Percentage of green squares = (43/50) x 100%
Percentage = 86%
If it’s a square. Take the area and cube root it.
That gives us 7.
7 + the four sides the square has = 7 + 7 + 7 + 7
That equals 28.
The answer is B.