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tatyana61 [14]
3 years ago
12

Select each expression that is equivalent to 5(n + 4).

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
7 0

Answer:

B and C and D

Step-by-step explanation:

scoray [572]3 years ago
5 0

Answer:

The Answer is B. C. and D.

Step-by-step explanation:

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my water sprinkler turns 5 degrees with every click. if it turns 60 degrees total, how many times has it clicked?
Ket [755]
12 times because you divide 60 by 5 and get 12.
4 0
3 years ago
What is -15 in integers
Paladinen [302]

The number -15 represents in a negative integer

<h3>How to determine what -15 represents in integers?</h3>

The number is given as:

Number = -15

Integers are numbers that do not have decimal points

The categories of integers are:

  • Positive integers (i.e. numbers greater than 0)
  • Zero
  • Negative integers (i.e. numbers less than 0)

The given number -15 is less than 0

Hence, the number -15 represents in a negative integer

Read more about integer at

brainly.com/question/17695139

#SPJ1

7 0
1 year ago
Write the subtraction problem below as an equation
Blababa [14]
Needs more information
6 0
3 years ago
The density of ice is approximately 0.92 g/cm3 . If a block of ice has a volume of 2300 cm3, what is its mass?
Mumz [18]

Answer:

The mass of the ice block is 2116 grams ⇒ a

Step-by-step explanation:

The formula of density is p=\frac{m}{V} , where m is the mass and V is the volume

To find the mass from this formula multiply both sides by V,

then m = p.V

∵ The density of ice is approximately 0.92 g/cm³

∴ p = 0.92

- That means the mass of 1 cm³ is 0.92 g

∵ The volume of an ice block is 2300 cm³

∴ V = 2300

- Use the formula of the mass

∵ m = p.V

- Substitute the values of p and V in it

∴ m = (0.92)(2300)

∴ m = 2116 grams

The mass of the ice block is 2116 grams

7 0
3 years ago
I suck at math can someone help please??
Zielflug [23.3K]
6/7 × 4 would be the correct answer. This is because 6/7 × 4= 3 3/7 which is equal to 4/7 × 6= 3 3/7. No other expression would equal 4/7 × 6
7 0
3 years ago
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