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notsponge [240]
3 years ago
15

from 5 employees at a company a group of 3 employees will be chosen to work on a project. how many different groups of 3 employe

es can be choosen?
Mathematics
1 answer:
sattari [20]3 years ago
5 0
The answer to the math question presented above would be 10. <span>From 5 employees at a company a group of 3 employees will be chosen to work on a project, the number of different groups of 3 employees can be chosen is 10. You can have 10 different groups of threes in 5 employees.</span>
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An accessories store sells $8 custom socks and $11 custom hats. If 11 items were sold on Monday, and the
Vanyuwa [196]

Answer:

7 socks were sold

Step-by-step explanation:

7*8=56

11-7=4

4×11=44

56+44=100

This proves the answer of 7 to be correct

7 0
2 years ago
Humberto evaluates the expression 4t2 for t=3. He correctly substitutes 3 for t in the expression, but then says that the value
AveGali [126]

Answer:

36

Step-by-step explanation:

He multiplied the four and the three first when he multiplied the equation together. However, according to the order of the operations, he was supposed to square three first. 3^2 = 9. Then multiplied 9*4 = 36.

4 0
3 years ago
During elementary school, Derek received a weekly allowance of $10 for completing all of his chores. These days he receives 50%
FrozenT [24]
Dereks weekly allowance is now $15. 50% of 10 is 5.

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5 0
2 years ago
Read 2 more answers
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
2 years ago
Sally scored 9.007 in gymnastics. Jack scored 8.949. How much higher was sally scored than jack’s
insens350 [35]

Answer:

0.058

Step-by-step explanation:

3 0
3 years ago
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