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3 years ago

What's the reciprocal of 1/7

Mathematics

2 answers:

Nonamiya [84]3 years ago

8 0

The answer is 7/1, when you want to know a reciprocal, all you do to the fraction is flip it around. Hope this Helps!

Vadim26 [7]3 years ago

8 0

the answer is 7/1 just flip it around

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Factor 54c–9d. Write your answer as a product with a whole number greater than 1

lisov135 [29]

Answer:

9(6c - d)

Step-by-step explanation:

$54c - 9d \\ = 9 \times 6c - 9d \\ = 9(6c - d) \\$

5 0

3 years ago

PLEASE HELP ME! BRAINLEST IF CORRECT

Whitepunk [10]

Answer:

x = 147

Step-by-step explanation:

33 and x form a straight line which means they add to 180

x+33 =180

x = 180-33

x = 147

4 0

3 years ago

Read 2 more answers

Implicit differentiation of 1/x +1/y=5 y(4)= 4/19<br> y'(4)=?

Aneli [31]

$\frac{1}{x} +\frac{1}{y} = 5\\\\x^{-1}+y^{-1}=5\\$

Above, I changed the fraction form of x and y into exponential form so it is easier to see the differentiation. Now, we can differentiate:

$-1x^{-2}+-1y^{-2}\frac{dy}{dx}=5\\\\\frac{-1}{x^2}-\frac{1}{y^2}\frac{dy}{dx}=5\\\\-\frac{1}{y^2}\frac{dy}{dx}=5+\frac{1}{x^2}\\\\\frac{dy}{dx}=-5y^2-\frac{y^2}{x^2}$

Now that we have dy/dx, we can plug in the x, which is 4, and the y, which is 4/19. We know these values of x and y because your question stated y(4) = 4/19.

$\frac{dy}{dx}=-5(\frac{4}{19})^2-\frac{(\frac{4}{19})^2}{(4)^2}\\\\\frac{dy}{dx}=-5(\frac{16}{361})-\frac{(\frac{16}{361})}{16}\\\\\frac{dy}{dx}=\frac{-80}{361}-\frac{1}{361}\\\\\frac{dy}{dx}=\frac{-81}{361}$

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4 years ago

9. Find (f.g)(a) if f(a) = . and g(a) = 2². Fully simplify your answer.

Aleks04 [339]

D is your answer ....

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3 years ago

I wasn't in class so I need help solving the inequality 7/10n+14<49

NikAS [45]

Answer:

n<50

Step-by-step explanation:

7/2*5n + 14<49

7n/2*5+14<49

(7n)+(2*5)14/2*5 <49

7n+10*14/2*5 <49

7n+140/2*5 <49

7n+140/10 <49

7n+140 < 10*49

7n+140 < 490

(7n+140)+(-140)<490+(-140)

7n+140-140<490-140

7n<350

7n/7 < 350/7

n<2*5^2*7/7

n<2*5^2

n<2*25

n<50

8 0

3 years ago