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Anna007 [38]
3 years ago
8

How much material would you need to fill the following cylinder? Radius 13 in. and Height 9 in.

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

1521 pi in^3

radius x radius x height x pi = volume

13 x 13 x 9 = 1521

We do not multiply by pi because it is already included

Hope this helps

Step-by-step explanation:

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inna [77]
She underestimated by 60 cents. To get this answer all you need to do is multiply 1 dollar times 12 which is $12 and then multiply $.30 by 12 and that gives you $3.60. Then you add the $12 to the $3.60 and that gives you $15.60 which is 60 cents over the estimation.
6 0
4 years ago
The segments shown below could form a triangle?
Leni [432]

Answer:

<em>Option B; False</em>

Step-by-step explanation:

Consider a Triangle Inequality to prove that these segments could form a triangle;

| a - b | < c < a + b,\\| c - a | < b < a + c,\\| c - b | < a < b + c, Considering - a - segment AC ( 8 units ) - b - BC ( 7 units ), -  c - BC ( 15 units )\\\\| 8 - 7 | < 15 < 8 + 7,\\1 < 15 < 15, Now 15 is not < 15, it is =, thus ;\\Solution ; False

<em>These segments could not form a triangle</em>

3 0
3 years ago
Read 2 more answers
Emily and Fred each have some money.
Crank

Answer

<em>A</em><em>s</em><em>s</em><em>a</em><em>l</em><em>a</em><em>m</em><em> </em><em>w</em><em>a</em><em>l</em><em>i</em><em>a</em><em>k</em><em>u</em><em>m</em><em> </em>

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I don’t know how to find the LCM for this.
nekit [7.7K]

Answer:

B

Step-by-step explanation:

7mn³|7m²n³ ---14mn^5

       | m---2n²

LCM=7mn³×m×2n²

=14m²n^5

or LCM of 7,14 =14

Highest power of m=2

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LCM=14m²n^5

6 0
3 years ago
Can anyone please explain? Need some help :)
DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = \dfrac{\sqrt{3} }{4}s^2

Side Length, s=6 Units

\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units

Area of the Hexagon

= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)

7 0
4 years ago
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