Make a frequency table to show the following test times (in minutes) for a reading test. 81, 63, 61, 58, 72, 70, 79, 68, 82, 64,
kodGreya [7K]
Sorry about my handwriting. this is what your graph should look like
Answer:
a)
_b+_=_
6B+3=75
B)
He ordered 12 books
Step-by-step explanation:
so each book (b) costs $6. he payed $75 total including the $3 shipping price
That gets us:
6b+3=75
6b=72
b=12
Therefore, Tom ordered 12 books
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job
We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)
We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability
P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate
Convert this to a percentage to get roughly 36.67% and this rounds to 37%
Final Answer: 37%
Answer:
5280, so not quite any of those, but the closest one is D
Try this option:
way 1: using the picture, if x=-3 then y=-6.
way 2: the equation of this line is y=x-3; it means that y(-3)=-6.
