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2 years ago

HELP!! What is the approximate measure of angle x in the triangle shown?

Mathematics

1 answer:

Alex Ar [27]2 years ago

6 0

<h3>Answer: D) 130.5 degrees</h3>

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Work Shown:

$c^2 = a^2 + b^2 - 2*a*b*\cos(C)\\\\10^2 = 5^2 + 6^2 - 2*5*6*\cos(x)\\\\100 = 25 + 36 - 60*\cos(x)\\\\100 = 61 - 60*\cos(x)\\\\100 - 61 = - 60*\cos(x)\\\\39 = - 60*\cos(x)\\\\\cos(x) = \frac{39}{-60}\\\\\cos(x) = -0.65\\\\x = \arccos(-0.65)\\\\x \approx 130.5416\\\\x \approx 130.5\\\\$

Note: I used the law of cosines. Make sure your calculator is in degree mode.

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