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galina1969 [7]
3 years ago
11

What is the domain for x is less than or equal to 5

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

54321

Step-by-step explanation:

or any negative number

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When comparing the functions using the equation, which conclusion can be made?
ankoles [38]

Answer:

  domain of f(x) is x ≤ 0; domain of f^-1(x) is x ≥ 4

Step-by-step explanation:

The square root function will always give a positive value, so the opposite of the square root function will give non-≤positive values. That means ...

  • the domain of f(x) is restricted to non-positive values
  • the domain of the inverse function is restricted to values of x that make the root be of a non-negative number: x ≥ 4

The domain of f(x) is x ≤ 0; the domain of f^-1(x) is x ≥ 4.

8 0
3 years ago
What is the angle B measurement. Urgent! Brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
forsale [732]

Answer:

52°

Step-by-step explanation:

both the triangle and the line equal 180 so, 180-127=53 53+75=128 180-128=52

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3 years ago
A polymer is manufactured in a batch chemical process. Viscosity measurements show that it is approximately normally distributed
PilotLPTM [1.2K]

Answer: (751.05, 766.95)

Step-by-step explanation:

We know that the confidence interval for population mean is given by :-

\overline{x}\pm z*\dfrac{\sigma}{\sqrt{n}},

where \sigma =population standard deviation.

\overline{x}= sample mean

n= sample size

z* = Two-tailed critical z-value.

Given :  \sigma= 20

n= 42

\overline{x}=759

We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576

Now, the 99% confidence interval around the true population mean viscosity :-

759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)

∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)

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3 years ago
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Orlov [11]

Answer:43 teaches

Step-by-step explanation:I research it

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Which of the following equations is for a cotangent function having a period of pi/2
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Answer:

C............,........

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