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IgorLugansk [536]
3 years ago
14

What's the answer to this?? I've tried 10 times and I can't solve it. Please help me!!

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0

Answer:

whats the question

Step-by-step explanation:

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A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr
miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88     Eqn 1

5x+2y=25      Eqn 2

Multiplying Eqn 2 by 4

4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\

Subtracting Eqn 1 from Eqn 3

(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12

Dividing both sides by 8

\frac{8x}{8}=\frac{12}{8}\\x=1.5

Putting x=1.5 in Eqn 1

12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70

Dividing both sides by 8

\frac{8y}{8}=\frac{70}{8}\\y=8.75

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/11334714
  • brainly.com/question/11345547

#LearnwithBrainly

5 0
2 years ago
Find the m∡B to the nearest tenth of a degree if cos B = 0.8926 and ∡B is an acute angle
mrs_skeptik [129]

Answer:

26.8°

Step-by-step explanation:

The cosine of an angle is the ratio of the adjacent side of the triangle in which the angle is formed to the hypotenuses side of the triangle. The cosine of the angle gives the ratio of these sides. However, the arc cosine of the ratio gives the angle measured in degrees.

If cos B = 0.8926

then arc cosine 0.8926  which may be expressed as cos-1 0.8926 will give the value of B.

B = cos-1 0.8926

= 26.8°

7 0
3 years ago
Please help <br><br> 2x^2 = y^3 x=2, y=?
andriy [413]

y is also 2.

2x^2 = 8

2^3 = 8

5 0
3 years ago
Read 2 more answers
Solve the quadratic equation by completing the square.
Step2247 [10]

Answer:

x1, x2 = 4.74 , -2.74

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 2x - 13

a = 1     b = -2    c = -13

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (2 + √ (2^2 - 4 * 1 * (-13)))/2 * 1

x1 = (2 + √ (4 + 52)) / 2

x1 = (2 + √ 56 ) / 2

x1 = (2 + 7.48) / 2

x1 = 9.48 / 2

x1 = 4.74

x2 = (2 - √ (2^2 - 4 * 1 * (-13)))/2 * 1

x2 = (2 - √ (4 + 52)) / 2

x2 = (2 - √ 56 ) / 2

x2 = (2 - 7.48) / 2

x2 = -5.48 / 2

x2 = -2.74

6 0
3 years ago
How can the next term in the infinite sequence 1,5,12,22,35.... be generated ?
lukranit [14]

Answer:

5322 21 es respusta dissso queridoo burro

7 1
3 years ago
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