Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer: a continuous random variable
Step-by-step explanation:
<u><em>Can you count the distance it traveled?</em></u> You can't, so it couldn't be discrete because you can count discrete variables.
<u><em>Can you measure the distance it traveled? </em></u>You sure can, that makes it a continuous random variable.
<u><em>Do you know the exact distance it's going to travel?</em></u><u> </u>You won't, therefore it's a random variable since you don't know the value beforehand.
Answer:
The answer is 7 1/24
Step-by-step explanation:
27/8 + 11/3
I multipled 27/8 by 3/3 (needed the 8 to become 24)
I multiplied 11/3 by 8/8 (needed the 3 to become 24)
We get:
81/24 + 88/24
Then you add
169/24
Simplify
7 1/24
Answer:
Step-by-step explanation:
In a quadratic equation in the Standard form
You need to remember that "a", "b" and "c" are the numerical coefficients (Where "a" is the leading coefficient and it cannot be zero: 
).
You can observe that the given quadratic equation is written in the Standard form mentioned before. This is:
Therefore, you can identify that the values of "a", "b" and "c" are the following:
Answer:
3
Step-by-step explanation:
