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zhannawk [14.2K]
3 years ago
5

The function ​f(x)​ is the height of a model rocket x seconds after launch.

Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

The practical domain for the function f(x) will be [0,5].

Step-by-step explanation:

A model rocket is launched from the ground and its height from the ground is given by f(x), t seconds after its launch.

It is given that the rocket reaches maximum height at t = 2.5 seconds and comes back to the ground after t = 5 seconds.

So, at t = 0 seconds, the rocket was at the ground and hence, t can not be negative and after t = 5 seconds the rocket comes back to the ground and hence, t can not be greater than 5 seconds.

Therefore, the practical domain for the function f(x) i.e. the values of t lies in the interval [0,5]. (Answer)

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How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman
OLga [1]

The number of possible batting lineups is 720

<u><em>Explanation</em></u>

Total number of players in the team = 9

The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, <u>3 slots in the batting line-up are already assigned to 3 players</u>.

So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.

Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be:  6! = 6*5*4*3*2*1=720

4 0
3 years ago
A recipe that makes 6 servings calls for 1/2 cup of butter. Nancy modifies the recipe so that it can serve 8
Maurinko [17]
<span>6 servings ... 1/2 cup of butter
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</span>6 * x = 8 * 1/2<span>
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x = 4/6
x = 2/3

Result: Nancy needs</span> 2/3 cup of butter for 8 servings.
7 0
3 years ago
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Step-by-step explanation:

1)......mean= sum of observations/ total observations

= 5.2+8.4+4.3+6.7+5.8/5= 6.08

median= n=5(odd)=n+1/2=6/2=3rdterm= 5.8( when arranged in ascending order).....

mode= 3median- 2meam= 3×5.8-2×6.08= 5.24

range=8.4-4.3=4.1(when done A.O)

2)......mean= -2-13-13-5-7/5= -8

median= 3rd term= -5.....(n=5..odd)(when done A.o)

mode=largest frequency= -13

range= -13-(-2) = -13+2= -11(A.O)

3).....mean= sum/no.= 8+6+13/2+17/2+15/2+7+8+11/2+7+8//10=7.2

median=n=10(even)

=

mode= 8

range=8.5-5.5=3

median:==

(10/2)+(10/2+1)//2=5 term + 6term/2=7+7.5=14.5/2=7.25

4)....

5)...remove 62...then 73will be having highest frequency

3 0
3 years ago
Can someone simplify? I'm confused-
Vladimir79 [104]
(64/56)^2 x (1/343) x 7^-9

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90,000
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