Answer:
Step-by-step explanation:
One angle is greater than 90°: Obtuse triangle
Two sides are the same length: Isosceles triangle
Answer: y = (x +2)² + 5
<u>Step-by-step explanation:</u>
y = a(x - h)² + k <em>where "a" is the leading coefficient and (h, k) is the vertex</em>
Since we don't know "a", we need to plug in the point (x, y) and the vertex (h, k) to solve for "a": (x, y) = (0, 9) and (h, k) = (-2, 5)
y = a(x - h)² + k
9 = a(0 - (-2))² + 5
9 = a(0 + 2)² + 5
9 = a(2)² + 5
<u>-5 </u> <u> -5 </u>
4 = a(4)
<u>÷4 </u> <u> ÷4 </u>
1 = a
Next, plug in "a" and the vertex (h, k):
y = a(x - h)² + k
y = 1(x +2)² + 5
y = (x +2)² + 5
Answer:
i think the answer is B hope i was helpful
Step-by-step explanation:
Answer:
S(x) = x² + 390224/x
Step-by-step explanation:
Volume of the open box = V = 97556 cm³
Material needed:
Let´s call x the side of the square base then the area of the base is
A(b) = x²
For the sides of the box, we have 4 sides each one with area of x*h
where h is the height of the box
The volume of the box V(b) = 97556 = x²*h then h = 97556/x²
S(x,h) = x² + 4*x*h*
The surface area of the box as function of x is:
S(x) = x² + 4*x*97556/x²
S(x) = x² + 390224/x
Answer:
I don't think it can, because the two smaller sides cannot have a sum of less than the third side. 6+6=12, and 12 is less than 15, so it cannot be possible. You can even test this out on a piece of paper and you will see that it is not possible.
