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marishachu [46]
3 years ago
10

The perimeter of a playing field for a certain sport is 300ft. The field is a rectangle, and the length is 48ft longer than the

width. Find the dimensions
Mathematics
2 answers:
lara31 [8.8K]3 years ago
4 0

Answer:

Width of the rectangular field =102 feet

Step-by-step explanation:

Perimeter of the field= 300feet

Length of the field= 48 feet

Width=?

Perimeter of a rectangular field= 2(Length+Width)

                                            300= 2(48+Width)\\\\150=48+Width\\\\Width=150-48\\\\Width=102 feet

The Width of the rectangular field is 102 feet

Oksana_A [137]3 years ago
3 0

Answer: the length is 99 feet and the width is 51 feet.

Step-by-step explanation:

Let L represent the length of the playing field.

Let W represent the width of the playing field.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of a playing field for a certain sport is 300ft. This means that

2(L + W) = 300

Dividing through by 2, it becomes

L + W = 150 - - - - - - - - - - - --1

The field is a rectangle, and the length is 48ft longer than the width. This means that

L = W + 48

Substituting L = W + 48 into equation 1, it becomes

W + 48 + W = 150

2W + 48 = 150

2W = 150 - 48

2W = 102

W = 102/2

W = 51

L = W + 48 = 51 + 48

L = 99

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In this question we have an equation that can be solved by <em>algebraic</em> definitions and theorems, whose objective consists in clearing the variable x. Now we proceed to solve the equation for x:

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