Question

The perimeter of a playing field for a certain sport is 300ft. The field is a rectangle, and the length is 48ft longer than the width. Find the dimensions

Answer 1

Answer:

Width of the rectangular field =$102 feet$

Step-by-step explanation:

Perimeter of the field= $300feet$

Length of the field= $48 feet$

Width=?

Perimeter of a rectangular field= $2(Length+Width)$

                                            $300= 2(48+Width)\\\\150=48+Width\\\\Width=150-48\\\\Width=102 feet$

The Width of the rectangular field is $102 feet$

Answer 2

Answer: the length is 99 feet and the width is 51 feet.

Step-by-step explanation:

Let L represent the length of the playing field.

Let W represent the width of the playing field.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of a playing field for a certain sport is 300ft. This means that

2(L + W) = 300

Dividing through by 2, it becomes

L + W = 150 - - - - - - - - - - - --1

The field is a rectangle, and the length is 48ft longer than the width. This means that

L = W + 48

Substituting L = W + 48 into equation 1, it becomes

W + 48 + W = 150

2W + 48 = 150

2W = 150 - 48

2W = 102

W = 102/2

W = 51

L = W + 48 = 51 + 48

L = 99