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viktelen [127]
3 years ago
12

Evaluate the following expression: 12 – 10 + 5 - 11. Remember to show your work

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

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A matched-pairs t-test is NOT an appropriate way to analyze data consisting of which of the following? Measurements of annual in
o-na [289]

Answer:

Step-by-step explanation:

A matched pair t test is one in which the set of data is divided into two sets of data and the test is done to test the difference between the pairs. Sometimes this is called paired t test.\

This is done normally where one group of sample or population can be paired with other group of sample /population.

Hence

A .Measurements of annual income for each twin for 100 randomly selected pairs of twins -- True

B. Measurements of annual income for both individuals in pairs formed by matching 100 people from State A and 100 people from State B based on level of education -- True

C. Measurements of annual income for both individuals in pairs formed by assigning 100 people to pairs at random -- True

D. Measurements of annual income recorded for both spouses of 100 randomly selected married couples  --False here we cannot say paired as these people are not grouped under the same conditions.

7 0
3 years ago
Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
Readme [11.4K]
<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

i.e. t=\dfrac{41.0-35.0}{\dfrac{3.7}{\sqrt{20}}}=7.252112359\approx7.25

Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

So we reject the null hypothesis, it means we have enough evidence to support the alternative hypothesis.

We conclude that there is some significance difference between the mean score for sober women and 35.0.

3 0
3 years ago
Erin gets her exercise by running. The graph shows the distances she covers in a given amount of time. How many hours does it ta
DaniilM [7]

Answer:

2½ h  

Step-by-step explanation:

Assume the graph is like the one below.

The graph shows how Erin's distance varies with time.

To find out how long it takes Erin to cover 25 mi, find 25 mi on the vertical axis.

From there, draw a horizontal line until it hits the graph.

Then drop a vertical line to the horizontal axis.

It hits half-way between 2 and 3.

It takes Erin 2½ h to run 25 mi.

7 0
3 years ago
Read 2 more answers
Use common factors to write two fractions equivalent to 80/140
9966 [12]

Answer:

80/140 = (80:20)/(140:20) = 4/7

4/7 = (4*4)/(7*4) = 16/28

4/7 = (4*5)/(7*5) = 20/35 not 20/28 not 20/32

4/7 = (4*5.5)/(7*5.5) = 22/38.5 not 22/37

3 0
3 years ago
Read 2 more answers
4.58+y=2.5<br><br> y= ??????
zepelin [54]

Answer:

-2.08

Step-by-step explanation:

If you just switch the problem, to make it 4.58-2.5, you get negative 2.5

6 0
3 years ago
Read 2 more answers
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