Answer:
b
Step-by-step explanation:
Using the trigonometric identity
secx =
and cos60° = 
Given
sec [
] ← evaluate bracket
= sec60°
= 
= 
= 2 → b
<span>The question is which answer does show the standard form of the equation: 7-3(x-y)=-5x+2. To see that let's transform our equation into standard form. Standard form of a linear equation is: ax+by=c. So our equation is: 7-3x+3y=-5x+2. Now we put the unknowns on the left and the numbers on the right: -3x+5x+3y=2-7 and we get 2x+3y=-5. And we see that the correct answer is C. </span>
ACD by AAS.
We're given m1 = m2, ADC = ADB, and both triangles share AD, so it must be AAS.
ABD by SAS.
We're given AB = AE and AC = AD, but the middle part is a mystery. We're not given BD and CE/ADB and ACE so it's pretty hard to know. Could be SAS or SSS. If you have either BD and CE, it's SSS. If you have ADB and ACE, it's SAS.
Took Geometry 4 years ago so I'm a bit iffy on the second. Forgive me D:
We have been given a system of equations
and
. We are asked to find the solution of our given system of equations.
To solve our system of equations, we will equate both equations as:









Upon substituting
in equation
, we will get:



Therefore, the solution of our given system of equations would be
and option A is the correct choice.
Answer:
sorry i cannot draw it right now
Step-by-step explanation:
I wil do the radian of the degrees
London: 0.013439
Glasgow: 6.21337
Leeds: 0.00628319
Guernsey: 2.82743