Answer:
2.51 < σ < 3.92
Step-by-step explanation:
We will use Chi-Square distribution to create the interval. We have the following information:
n = 41
Level of Confidence : 95%,
This corresponds to Chi-Square values of:
24.433 for the left tail and 59.342 for the right tail
We need to calculate the sample Variance. This is done on attached photo 1 (the shortcut formula for finding variance was used)
We get s = 9.3866.
See the construction of the confidence interval on the second attached photo
<span>
Exercise #1:
Point H = (–2, 2)
Point J = (–2, –3)
Point K = (3, –3)
It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points J and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.
Notice that point-J is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-J is one corner of the square.
H is another corner of the square. It's 5 units above J.
K is another corner of the square. It's 5 units to the right of J.
The fourth corner is (2, 3) ... 5 to the right of H,
and 5 above K.
____________________________________
Exercise #2:
</span><span>Point H = (6, 2)
Point J = (–2, –4)
Point K = (-2, y) .
</span><span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
</span><span>Notice that points J and K have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
We need K to connect to point-H in such a way that it's on
the same horizontal line as H. Then the vertical and horizontal
lines that meet at K will be perpendicular, and we'll have the
right angle that we need there to make the right triangle.
So K and H need to have the same y-coordinate.
H is the point (6, 2). So K has to be up at (2, 2) .
____________________________________________
Exercise #3:
</span>
<span>Point H = (-6, 2)
Point J = (–6, –1)
Point K = (4, 2) .
</span>
<span>It would be very helpful if you could take a pencil and a piece
of paper, and sketch a graph with these points on it. Then
you'd immediately see what's going on.
This exercise is exactly the same as #1, except that it's a
rectangle instead of a square. It's still make of horizontal
and vertical lines, and that's all we need to know in order
to solve it.</span><span>
Notice that points H and J have the same x-coordinate, but
different y-coordinates, so they're on the same vertical line.
</span><span>Notice that points H and K have different x-coordinates but
the same y-coordinate, so they're on the same horizontal line.
Notice that point-H is on both the horizontal line and the vertical
line, so the lines meet there, and they're perpendicular.
Point-H is one corner of the rectangle.
J is another corner of the rectangle. It's 3 units below H.
K is another corner of the square. It's 4 units to the right of H.
The fourth corner is (2, -1) ... 4 to the right of J,
and 3 below K.
</span>
Step-by-step explanation:
First solve for y,
7-y<2x
7-2x<y
y>-2x+7
your y intercept would be (0,7)
and your slope would be -2/1 so, you go down 2 and 1 to the right.
Since this is a greater than symbol, we have to shade above the line and the line would also be a dotted line.
Answer:
19
Step-by-step explanation:
Substitute the values and use the order of operations to find the correct value.
q · s + r
2 · 5 + 9
10 + 9
19
The required value after simplification of the s = -16/3. None of these are correct.
Given that,
To simplify ![[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bx%5E%7B2%2F3%7Dx%5E%7B-1%2F2%7D%7D%7Bx%5Csqrt%7Bx%5E3%7D%5Csqrt%5B3%5D%7Bx%7D%7D%5D%5E2)
and to find the value of s in 
.
<h3>What is simplification?</h3>
The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.
Simplification,
![=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7Bx%5E%7B2%2F3%7Dx%5E%7B-1%2F2%7D%7D%7Bx%5Csqrt%7Bx%5E3%7D%5Csqrt%5B3%5D%7Bx%7D%7D%5D%5E2%5C%5C%3D%20%5Cfrac%7Bx%5E%7B4%2F3%7Dx%5E%7B-1%7D%7D%7Bx%5E2x%5E3%2A%7Bx%7D%5E%7B2%2F3%7D%7D%5C%5C%3D%20%5Cfrac%7Bx%5E%7B1%2F3%7D%7D%7Bx%5E%7B17%2F3%7D%7D%5C%5C%3Dx%5E%7B-16%2F3%7D)
Comparing with 
s = -16/3
Thus, the required value of the s = -16/3. None of these are correct.
Learn more about simplification here: brainly.com/question/12501526
#SPJ1
