A storage unit is cubical in shape. Each

The population of a certain island has an annual growth rate of 6.9%. If you start with a poplulation of 2500 people, what would

masya89 [10]

1,725 is you answer because you growth rate is 172.5 a year x ten is 1725

3 0

3 years ago

If f(x) = 3x - 7, then f-1(x)=

fgiga [73]

Answer:

Step-by-step explanation:

so f-1(x) means we are finding the inverse

f(x) = 3x - 7.....change f(x) to y

y = 3x - 7.....now switch ur x and y and solve for y

x = 3y - 7....add 7 to both sides

x + 7 = 3y...divide both sides by 3

(x/3) + 7/3 = y....rearrange

y = (x/3) + 7/3....can also be written as : y = 1/3x + 7

now just change ur y to f-1(x)

f-1(x) = x/3 + 7/3.....or f-1(x) = 1/3x + 7/3

4 0

3 years ago

Read 2 more answers

is vector v with an initial point of (-5,22) and a terminal point of (20,60) equal to vector u with an intintal point of (50,120

marta [7]

Answer:

Yes, vectors u and v are equal.

Step-by-step explanation:

We need to check whether vectors u and v are equal or not.

If the initial point is $(x_1,y_1)$ and terminal point is $(x_2,y_2)$ , then the vector is

$Vector=(x_2-x_1)i+(y_2-y_1)j$

Vector v with an initial point of (-5,22) and a terminal point of (20,60).

$\overrightarrow v=(20-(-5))i+(60-22)j$

$\overrightarrow v=25i+38j$ ..... (1)

Vector u with an initial point of (50,120) and a terminal point of (75,158).

$\overrightarrow u=(75-50)i+(158-120)j$

$\overrightarrow u=25i+38j$ .... (2)

From (1) and (2) we get

$\overrightarrow u=\overrightarrow v$

Therefore, vectors u and v are equal.

5 0

3 years ago

How many multiples of 4 are there in {n; 37< n <1001}?

s2008m [1.1K]

Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.

Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:

<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:

1000
-40
-------
960

Dividing this by 4, we get 240. Adding 1, we get 241.

Finally, subtract 9 from 241: We get 232.

There are 232 multiples of 4 between 37 and 1001.

Can you think of a more straightforward method of determining this number? </span>

5 0

3 years ago

Determine to the nearest and tenth the surface area of a tin can with a radius of 8 centimeters and a height of 16 centimeters

trapecia [35]

Answer:

1206 square centimeters

Step-by-step explanation:

Hello, I can help you with that

a tin is a cylinder,a cylinder is formed by 2 circles anda 1 rectangle

let's remember

Area of the circle

$A=\pi *radius^{2}$

Area of the rectangle

$A_{r}=length *wide\\$

the length of the rectangle is the height of the tin (16 cm)

and the wide is equal to the perimeter of the circle

perimeter of the circle(P)

$P=2*\pi *radius$

so, the area of the rectangle is

$A_{r}=length *wide\\\\A_{r}=heigth *2*\pi *radius$

Step one

find the total area:

the total area is equal to 2 circles + 1 rectangle

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)$

Step two

put the values into the equation

height = 16 cm

radius= 8 cm

$A_{total}=(2* \pi *radius^{2} )+(height*2*\pi *radius)\\A_{total}=(2* \pi )+(16*2*\pi *8)\\A_{total}=(128* \pi )+(256*\pi )\\A_{total}= 378 \pi\\ A_{total}=1206.37$

so, the total area is 1206.37 square centimeters

I hope it helps, have a great day.

6 0

2 years ago

Read 2 more answers