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JulijaS [17]
3 years ago
7

Please help me if you can

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
If you use an app called Socratic, take a photo of the questions and it will show you how to work it out and the answer and etc.

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Which color is the line that represents an equivalent ratio? How can you tell by looking at the lines? A) blue; The graph is a v
Genrish500 [490]

Answer:

C) pink; The graph of the pink line passes through the origin.

6 0
2 years ago
Write the reflation ship between the value <br> of the given digits<br> 6s in 660
olga2289 [7]
Hello Srahman1183 i get how adjetated u must be feeling right now having to wait 6 days to get this answer im about to give u but whatever. The relationship between them istheyare both partof the powers of ten, the first 6 is inthe 100 place and the second 6 is in the 10 place, hope this helped
5 0
3 years ago
I need help with the answers
vlada-n [284]

Answer:

i dont get it

Step-by-step explanation:

4 0
2 years ago
Unsure how to do this calculus, the book isn't explaining it well. Thanks
krok68 [10]

One way to capture the domain of integration is with the set

D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}

Then we can write the double integral as the iterated integral

\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx

Compute the integral with respect to y.

\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)

Compute the remaining integral.

\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}

We could also swap the order of integration variables by writing

D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}

and

\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy

and this would have led to the same result.

\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)

\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)

7 0
1 year ago
Is 8 one tenths of 80
Otrada [13]
Yeah 8 is 1/10th of 80.

6 0
3 years ago
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