You have 2 triangles and 3 rectangles.
Start with a triangle:
area is base side * height / 2 -> 4 * 3 / 2 = 6
The other triangle has the same area: 6
First rectangle: side * other side -> 7 * 5 = 35
Second rectangle: 7 * 4 = 28
Third rectangle: 7 * 3 = 21
Now simply add all this together: 6+6+35+28+21 = 96
1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Answer:
Because 0 counts as the first possible number. 0-9 gives you 10 possible numbers.
Step-by-step explanation:
It would be D
Your welcome ;)
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