Answer:
thanks for the free points
Step-by-step explanation:
When doing that it will be B
*Hint: When you have two y's, they could equal each other in order to solve for the x value.
|x^2 -3x + 1| = - (x - 1)
x^2 -3x + 1 = -x + 1
x^2 - 2x + 1 = 1
x^2 - 2x = 0
x (x - 2)
x = 2 and x = 0
Once both of them are plugged in, only x = 2 works so that's the value for x. Now we just plug it in order to solve for y.
y = x - 1
y = 2 - 1
y = 1
(2, 1)
The answer would be C.
