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goldenfox [79]
3 years ago
12

Which of the following transformations fit the definition of isometry?

Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0

Answer: Rotations, reflections, translations (A, C, and E)

Imagine you had a camera aimed at a triangular figure on a piece of paper. If you rotate the camera, then the image of the triangle appears to rotate. In reality it's the other way around. What this means is that the triangle is not changing at all. It keeps the same size, shape, area, perimeter, etc. This applies to when the camera pans left or right, ie shifts from side to side. The triangle will translate but again the triangle isn't changing at all. It's merely an illusion. Reflections are the same way. Imagine having a piece of glass or a mirror that reflects the image which is an identical copy; although everything is flipped.

Dilations are not isometries because the image is a different size then the pre-image. The same shape is maintained though. Note: the scale factor must be some number other than 1.

another note: "isometry" breaks down into "iso+metry" with "iso" meaning "same" or "equal", and "metry" meaning "measure". So if you had 2 identical yard sticks, then they are isometrical or equal in length.

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liraira [26]

Answer:

y=mx + b

the slope is -3,2

y= -0.67x + 5

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Step-by-step explanation:

8 0
3 years ago
I need help with this I put this out 3 times I need help
anzhelika [568]
Prompt
What is a row?
4 0
3 years ago
You start at (-1, 2). You move right 5 units and down 6 units. Where do you end?
Irina-Kira [14]

Answer:

(4,-4)

Step-by-step explanation:

Just plot it or like I did it like this

Since moving right or left is X axis, just add 5 to -1 becuase its ont he X axis

Then for the bottom and up, thats Y so subtract  that to the Y axis so 2-6=-4

4,-4

5 0
3 years ago
24 POINTS!!!!!!!!!!!
Sindrei [870]
<span>The angles are supplementary.</span>
6 0
4 years ago
Read 2 more answers
Find the area of the shaded region .
Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

2 \cdot \frac{1}{2}(6)(6) = 36 ft^2

Area of the two white quarter circles in the bottom left and top right:

2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2

Total area of unshaded white region inside circle:

(36 + 18\pi)ft^2

Area of entire circle including the white and shaded regions

\pi(6)^2 = 36\pi ft^2

Area of shaded region is area of entire circle - area of unshaded white region

36\pi - (36 + 18\pi) = (18\pi - 36) ft^2

7 0
3 years ago
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