Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer:
7)
Step-by-step explanation:
The pattern is: add two more than you did before: starting from 2.
It would be:
1, 3, 7, 13, 21, 31, 43, 57
+2 +4 +6 +8 +10 +12 +14
Now use this to answer the questions.
Hope this helped!
Have a nice day!
(it would be nice if you gave me brainliest)
Thx :)
No it is not, the square root is 8.3
