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3 years ago

What is equivalent to 13 - √-18? 4 13 - 9i 13 + 9i 22

Mathematics

1 answer:

beks73 [17]3 years ago

8 0

√-1=i

13-√-18=
13-√(-1)(18)=
13-(√-1)(√18)=
13-(i)(3√2)=
13-3i√2

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Multiply Conjugates Using the Product of Conjugates Pattern

weeeeeb [17]

Answer:

The product is the difference of squares is $\left(xy-9\right)\left(xy+9\right)={{x}^2}{{y}^2}-81$

Step-by-step explanation:

Explanation

The given expression is (x y-9)(x y+9).
We have to multiply the given expression.
Square the first term xy. Square the last term 9 .

$\begin{aligned}&(x y-9)(x y+9)=(x y)^{2}-(9)^{2} \\&(x y-9)(x y+9)=x^{2} y^{2}-81\end{aligned}$

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2 years ago

Two angles are supplementary. The measure of the larger angle is 4 more than 3 times the measure of the smaller angle. Find the

m_a_m_a [10]

Answer:

<u>The smaller angle measures 44° and the larger measures 136°</u>

Step-by-step explanation:

Let'e recall that supplementary angles are two angles whose sum is 180° degrees.

Smaller angle = x

Larger angle = 3x + 4

Therefore, we have:

x + 3x + 4 = 180

4x = 180 - 4

4x = 176

x = 176/4

x = 44 ⇒ 3x + 4 = 136

<u>The smaller angle measures 44° and the larger measures 136°</u>

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3 years ago

Judd worked 40 hours this week. He worked 7/10 of the hours outside and the rest inside. How many hours did he work outside?

Mnenie [13.5K]

If you would like to know how many hours did Judd work outside, you can calculate this using the following steps:

40 hours
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3 years ago

How much 74.3 - 18.26

Oksanka [162]

56.04 is the answer if im correct

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3 years ago

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In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t

Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

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34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

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2 years ago

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