Answer:
This is the alternate exterior angle theorem
Step-by-step explanation:
This is because angle 2 and angle 7 are in the <u>outer</u> part of each side of opposite lines
Aos= -b/2a so plunin your numbers and you'll get the AOS so you can find the vertex
B = block p = park
2b + p = 10 min 2 runs around the block takes 10 minutes
2b + 3p = 22 min 2 runs around the block plus 3 runs around the park takes 22 minutes
To solve, I will use substitution. First, I will divide the first equation by 2 to get b by itself and subtract p from both sides to get b by itself. Then, substitute 5 - 1/2p in for b in the second equation because they have equal values. Then, subtract 10 from both sides to eliminate it. Divide by 2 to both sides to get 'p' by itself.
2b + p = 10 min ---------→b + 1/2p = 5 ----------→ b = 5 - 1/2p
2(5 - 1/2p) + 3p = 22 ---------→ 10 -p + 3p = 22 --------→ 10 + 2p = 22
10 + 3p = 22 ----------→ 2p = 12
2p = 12 -------------→ p = 6
It takes 6 minutes to jog around the park
Hope this helps!
Answer:
x = 57/28
y = -95/84
z = 97/168
Step-by-step explanation:
Use the application in the next link: https://www.zweigmedia.com/RealWorld/tutorialsf1/scriptpivotold.html
Start with the expanded array:
![\left[\begin{array}{cccc}1&5&8&1\\3&2&2&5\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C3%262%262%265%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
then using the tool provided, make row operations until you find the solution:
r2 = r2-3r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\-2&-7&2&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C-2%26-7%262%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+2r1
![\left[\begin{array}{cccc}1&5&8&1\\0&-13&-22&2\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%26-13%26-22%262%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2*(-1/13)
![\left[\begin{array}{cccc}1&5&8&1\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%265%268%261%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r1 = r1- r2*5
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&3&18&7\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%263%2618%267%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3+ r2*-3
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&168/13&97/13\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%26168%2F13%2697%2F13%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r3 = r3*13/168
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&22/13&-2/13\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%2622%2F13%26-2%2F13%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2- r3*22/13
![\left[\begin{array}{cccc}1&0&-6/13&23/13\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26-6%2F13%2623%2F13%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
r2 = r2+ r3*6/13
![\left[\begin{array}{cccc}1&0&0&57/28\\0&1&0&-95/84\\0&0&1&97/168\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%2657%2F28%5C%5C0%261%260%26-95%2F84%5C%5C0%260%261%2697%2F168%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Here you have a reduced array an therefore the answers to each variable are on each row:
![\left[\begin{array}{c}x\\y\\z\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D)
10+5x+5y is the simplified version
