Length from R(-2, 4) to S(3, 4) is sqrt((3 - (-2))^2 + (4 - 4)^2) = sqrt(5)^2 = 5 units
Length from S(3, 4) to T(3, -1) is sqrt((3 - 3)^2 + (-1 - 4)^2) = sqrt(-5)^2 = 5 units
Therefore, total length = 5 + 5 = 10 units.
Answer:
Number 1= 5th vertical line
number 2= 2nd vertical line
number 3= halfway between 2nd and 3rd vertical line
Step-by-step explanation:
Answer:
-4y -12
Step-by-step explanation:
We cannot solve, but we can simplify
3(y-4)-7y
Distribute the 3
3y -12 -7y
Combine like terms
3y-7y -12
-4y -12
Answer:
A: a(t)
B: v(t)
C: s(t)
Step-by-step explanation:
One graph is position, s(t).
Another is velocity, v(t) = ds/dt (slope of the tangent line of the position curve).
The third is acceleration, a(t) = dv/dt (slope of the tangent line of the velocity curve).
If graph A is s(t), then velocity v(t) would always be positive. No graph fits, so A is not s(t).
If graph B is s(t), then velocity v(t) would start negative then become positive, like graph A does. If graph A is v(t), then acceleration a(t) would always be positive. No graph fits, so A is not v(t), which means B is not s(t).
If graph C is s(t), then velocity v(t) would always be negative, like graph B. If graph B is v(t), then acceleration a(t) starts negative then becomes positive, like graph A does.
Therefore:
A: a(t)
B: v(t)
C: s(t)
Answer:
Answer
Find out the how much money was in the account after 1\frac{1}{2} years.
To prove
Formula
Simple\ interest = \frac{Principle\times Rate\times time}{100}
As given
Tracy deposited $59 into a bank account that earned 3.5% simple interest each year.
Principle = $59
Rate = 3.5 %
Time = 1\frac{1}{2}
i.e
Time = \frac{3}{2}
Time = 1.5 years
Put all the values in the equation
Simple\ interest = \frac{59\times 3.5\times 1.5}{100}
= \frac{309.75}{100}[/tex]
= $3.1(approx)
Amount in the account = Principle + Simple interest
= $59 + $ 3.1
= $ 62.1
1 Dollar = 100 cent
Now convert $62.1 into cent.
= 62.1 × 100
= 6210 cent
Therefore the money in the account is 6210 cent .
