<em>Acceleration (a) = 5.1 m/s</em>²
<em>Initial speed (u) = 16 km/h </em>⇒

<em>m/s </em>≈ <em>4.5m/s</em>
<em>
</em><em>Final speed (v) =118 km/h </em>⇒

<em>m/s</em> ≈ <em>32.8m/s</em>
<em>
</em>Distance(S) travel in that particular instant is carried out by 'Third equation of motion' i.e., v² = u² + 2aS
<em>So, When all quantities are in S.I. unit then,
</em>putting the values in the equation of motion,
<em /><em>As we have to carry out the distance covered,
</em><em>2</em>·<em>a</em>·<em>S = v</em>² <em>- u</em>²
<em>S = </em>

Putting values in derived equation,
⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S = </em>

⇒ <em>S </em>≈ <em>103.489</em> <em>m
</em>
<em>
The total distance covered in that given condition is approx. 103.289 m.</em>
Answer:
6660 yards^2
Step-by-step explanation:
Assumption: the field is 120 yards long and 50 yards wide.
First calculate the area of the field: 120*50 = 6000 yards^2
Then, calculate the 11% of that area: 6000 yards^2*11/100 = 660 yards^2
Finally, the area of the tarp material should be 6000 yards^2 + 660 yards^2 = 6660 yards^2
Answer:
length =√area use this formula
C and then D because when you go outside and it’s cold then you know it’s cold
The answer is A i believe